Explanation Given information: Tube is subjected to an axial force of 10 N. Thickness of paper ( t ) is 1 mm. Outer diameter of the tube ( d 0 ) is 30 mm. Calculation: Calculate the normal stress ( σ ) acting on the tube using the relation: σ = N A (1) Here, N is the axial force and A is the area of the tube. The inner diameter ( d i ) of the tube is, d i = d 0 − 2 t = 30 mm − 2 ( 1 mm ) = 28 mm Find the area of the tube ( A ) using the relation: A = π 4 ( d 0 2 − d i 2 ) (2) Substitute 30 mm for d 0 and 28 mm for d i in Equation (2). A = π 4 ( 30 2 − 28 2 ) = 91.1062 mm 2 Substitute 10 N for N and 91.1062 mm 2 for A in Equation (1). σ = 10 N 91.1062 mm 2 = 0.10976 MPa = 109.76 kPa Find the shear stress ( τ ) acting on the cross section: Since there is no shear force in the cross section. Therefore the value of shear stress is 0

9th Edition

ISBN: 2810014920922

Author: HIBBELER

Publisher: PEARSON

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Chapter 9.3, Problem 9.38P

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The shear stress acting along the seam.

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Chapter 9.3, Problem 9.37P

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MECHANICS OF MATERIALS-TEXT

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