Explanation Given: Force of 80 pounds is acting in the direction of 50 ∘ to the horizontal in moving an object 12 feet from ( 0 , 0 ) to ( 12 , 0 ) . Formula used: Work done = force x distance moved in the direction of the force. Calculation: Force = 80 pounds...

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ISBN: 9780136166924

Author: Sullivan

Publisher: PEARSON

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Chapter 9.3, Problem 92AYU

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To find: The work done by a force of 80 pounds acting in the direction of $50^{\circ}$ to the horizontal in moving an object 12 feet from $(0, 0)$ to $(12, 0)$ .

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Chapter 9.3, Problem 91AYU

Chapter 9.3, Problem 93AYU

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The work done by a force of 80 pounds acting in the direction of 50 ∘ to the horizontal in moving an object 12 feet from ( 0 , 0 ) to ( 12 , 0 ) .

Solution Summary: The author explains the work done by a force of 80 pounds acting in the direction of 50 to the horizontal in moving an object 12 feet from ( 0 ) to ( 12 ).

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To find: The work done by a force of 80 pounds acting in the direction of $50^{\circ}$ to the horizontal in moving an object 12 feet from $(0, 0)$ to $(12, 0)$ .

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Chapter 9 Solutions

The work done by a force of 80 pounds acting in the direction of 50 ∘ to the horizontal in moving an object 12 feet from ( 0 , 0 ) to ( 12 , 0 ) .

Solution Summary: The author explains the work done by a force of 80 pounds acting in the direction of 50 to the horizontal in moving an object 12 feet from ( 0 ) to ( 12 ).

Concept explainers

Videos

To find: The work done by a force of 80 pounds acting in the direction of 50 ∘ to the horizontal in moving an object 12 feet from ( 0, 0 ) to ( 12, 0 ) .

Want to see the full answer?

Chapter 9 Solutions

To find: The work done by a force of 80 pounds acting in the direction of $50^{\circ}$ to the horizontal in moving an object 12 feet from $(0, 0)$ to $(12, 0)$ .