Concept explainers
a.
To find: The P -value using technology and table. Also, the conclusions that could be drawn using the significance levels 1% and 5%.
a.
Answer to Problem 69E
The P -value is 0.0431.
Explanation of Solution
Given:
The null and alternative hypotheses are:
Test statistic ( t ) = 1.81
Calculation:
From alternative hypothesis, it is known that the test is one tailed.
The degree of freedom is computed as:
The P -value using Ti-83 calculator can be computed as:
Now, P - value using table can be calculated as:
Thus, the P -value is 0.0431.
Here, P -value (0.0431) >
Conclusion:
Thus, at 1% significance there are insufficient evidence to conclude that
b.
To find: The P -value using technology and table. Also, the conclusions that could be drawn using the significance levels 1% and 5%.
b.
Answer to Problem 69E
The P -value is 0.086.
Explanation of Solution
Given:
The null and alternative hypotheses are:
Sample size ( n )= 20
Test statistic ( t ) = 1.81
Calculation:
From alternative hypothesis, it is known that the test is one tailed.
The degree of freedom is computed as:
The P -value using Ti-83 calculator can be computed as:
The above value is for one tailed.
The P -value for two tailed can be calculated as:
Here, also the P -value is 0.086.
Now, P - value using table can be calculated as:
Thus, the P -value is 0.086.
Here, P -value (0.086) >
Conclusion:
Thus, at 1% and 5% significance levels there are sufficient evidence to conclude that
Chapter 9 Solutions
The Practice of Statistics for AP - 4th Edition
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Statistics for Psychology
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Elementary Statistics: Picturing the World (6th Edition)
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