
Interpretation:
The oxygen (
Concept Introduction:
Molecular orbital (MO) theory: is a method for determining molecular structure in which electrons are not assigned to individual bonds between atoms, but are treated as moving under the influence of the nuclei in the whole molecule.
HOMO and LUMO: This statement stand for highest occupied molecular orbital (HOMO) and lowest unoccupied molecular orbital (LUMO), respectively. So this energy difference between the HOMO and LUMO is termed the HOMO–LUMO gap.
Valence shell electron pair repulsion (VSEPR) theory: It is a model used in chemistry to predict the geometry of individual molecules from the number of electron pairs surrounding their central atoms.

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Chapter 9 Solutions
Bundle: Chemistry & Chemical Reactivity, Loose-Leaf Version, 9th + OWLv2, 4 terms (24 Months) Printed Access Card
- Identify the compound with the longest carbon - nitrogen bond. O CH3CH2CH=NH O CH3CH2NH2 CH3CH2C=N CH3CH=NCH 3 The length of all the carbon-nitrogen bonds are the samearrow_forwardIdentify any polar covalent bonds in epichlorohydrin with S+ and 8- symbols in the appropriate locations. Choose the correct answer below. Η H's+ 6Η Η Η Η Η Ηδ Η Ο Ο HH +Η Η +Η Η Η -8+ CIarrow_forwardH H:O::::H H H HH H::O:D:D:H HH HH H:O:D:D:H .. HH H:O:D:D:H H H Select the correct Lewis dot structure for the following compound: CH3CH2OHarrow_forward
- Rank the following compounds in order of decreasing boiling point. ннннн -С-С-Н . н-с- ННННН H ΗΤΗ НННН TTTĪ н-с-с-с-с-о-н НННН НН C' Н н-с-с-с-с-н НН || Ш НННН H-C-C-C-C-N-H ННННН IVarrow_forwardRank the following compounds in order of decreasing dipole moment. |>||>||| ||>|||>| |>|||>|| |||>||>| O ||>>||| H F H F H c=c || H c=c F F IIIarrow_forwardchoose the description that best describes the geometry for the following charged species ch3-arrow_forward
- Why isn't the ketone in this compound converted to an acetal or hemiacetal by the alcohol and acid?arrow_forwardWhat is the approximate bond angle around the nitrogen atom? HNH H Harrow_forwardOH 1. NaOCH2CH3 Q 2. CH3CH2Br (1 equiv) H3O+ Select to Draw 1. NaOCH2 CH3 2. CH3Br (1 equiv) heat Select to Edit Select to Drawarrow_forward
- Complete and balance the following half-reaction in acidic solution. Be sure to include the proper phases for all species within the reaction. S₂O₃²⁻(aq) → S₄O₆²⁻(aq)arrow_forwardQ Select to Edit NH3 (CH3)2CHCI (1 equiv) AICI 3 Select to Draw cat. H2SO4 SO3 (1 equiv) HO SOCl2 pyridine Select to Edit >arrow_forwardComplete and balance the following half-reaction in basic solution. Be sure to include the proper phases for all species within the reaction. Zn(s) → Zn(OH)₄²⁻(aq)arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning


