Chapter 9.2, Problem 7P

Find the equation of the axis of symmetry and the coordinates of the vertex and the graph of each function.

$y=2x^2+x-14$

To determine

To find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function.

Answer to Problem 7P

From graph the axis of the symmetry is $x=-0.25$ and the vertex is $\left(-0.25,-14.125\right)$ .

Explanation of Solution

Given information: The function is, $y=2x^2+x-14$ .

Calculation: The required solution is obtained as,

  $y=2x^2+x-14$

Let $x=-0.25$

x	$y=2x^2+x-14$
-0.25	-14.125

Graph is,

  

Hence, from graph the axis of the symmetry is $x=-0.25$ and the vertex is $\left(-0.25,-14.125\right)$ .