Chapter 9.10, Problem 3QCE

$\left({\displaystyle \underset{k=0}{\overset{\infty }{\sum }}\frac{x^k}{k!}}\right)\left({\displaystyle \underset{k=0}{\overset{\infty }{\sum }}\frac{x^k}{k+1}}\right)=\left(1+x+\frac{x^2}{2!}+\mathrm{...}\right)\left(1+\frac{x}{2}+\frac{x^2}{3}+\mathrm{...}\right)=\text{\_\_\_\_\_\_\_}+\text{\_\_\_\_\_\_\_}x+\text{\_\_\_\_\_\_\_\_}{x}^2+\mathrm{...}$