Chemical rate equations The reaction of certain chemical compounds can be modeled using a differential equation of the form y′ ( t ) = –ky n ( t ), where y ( t ) is the concentration of the compound for t ≥ 0, k > 0 is a constant that determines the speed of the reaction, and n is a positive integer called the order of the reaction. Assume that the initial concentration of the compound is y (0) = y 0 > 0. a. Consider a first-order reaction ( n = 1) and show that the solution of the initial value problem is y ( t ) = y 0 e – kt . b. Consider a second-order reaction ( n = 2) and show that the solution of the initial value problem is y ( t ) = y 0 y 0 k t + 1 . c. Let y 0 = 1 and k = 0.1. Graph the first-order and second-order solutions found in parts (a) and (b). Compare the two reactions.
Chemical rate equations The reaction of certain chemical compounds can be modeled using a differential equation of the form y′ ( t ) = –ky n ( t ), where y ( t ) is the concentration of the compound for t ≥ 0, k > 0 is a constant that determines the speed of the reaction, and n is a positive integer called the order of the reaction. Assume that the initial concentration of the compound is y (0) = y 0 > 0. a. Consider a first-order reaction ( n = 1) and show that the solution of the initial value problem is y ( t ) = y 0 e – kt . b. Consider a second-order reaction ( n = 2) and show that the solution of the initial value problem is y ( t ) = y 0 y 0 k t + 1 . c. Let y 0 = 1 and k = 0.1. Graph the first-order and second-order solutions found in parts (a) and (b). Compare the two reactions.
Chemical rate equations The reaction of certain chemical compounds can be modeled using a differential equation of the form y′(t) = –kyn(t), where y(t) is the concentration of the compound for t ≥ 0, k > 0 is a constant that determines the speed of the reaction, and n is a positive integer called the order of the reaction. Assume that the initial concentration of the compound is y(0) = y0 > 0.
a. Consider a first-order reaction (n = 1) and show that the solution of the initial value problem is y(t) = y0e–kt.
b. Consider a second-order reaction (n = 2) and show that the solution of the initial value problem is
y
(
t
)
=
y
0
y
0
k
t
+
1
.
c. Let y0 = 1 and k = 0.1. Graph the first-order and second-order solutions found in parts (a) and (b). Compare the two reactions.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
3) If a is a positive number, what is the value of the following double integral?
2a
Love Lv
2ay-y²
.x2 + y2 dady
16. Solve each of the following equations for x.
(a) 42x+1 = 64
(b) 27-3815
(c) 92. 27² = 3-1
(d) log x + log(x - 21) = 2
(e) 3 = 14
(f) 2x+1 = 51-2x
11. Find the composition fog and gof for the following functions.
2
(a) f(x) = 2x+5, g(x) = x²
2
(b) f(x) = x²+x, g(x) = √√x
1
(c) f(x) = -1/2)
9
9(x) =
х
=
-
X
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A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
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