Drug infusion The delivery of a drug (such as an antibiotic) through an intravenous line may be modeled by the differential equation m′ ( t ) + km ( t ) = I , where m ( t ) is the mass of the drug in the blood at time t ≥ 0, k is a constant that describes the rate at which the drug is absorbed, and I is the infusion rate. a. Show by substitution that if the initial mass of drug in the blood is zero ( m (0) = 0), then the solution of the initial value problem is m ( t ) = I k ( 1 − e − k t ) . b. Graph the solution for I = 10 mg/hr and k = 0.05 hr –1 . c. Evaluate lim t → ∞ m ( t ) , the steady-state drug level, and verify the result using the graph in part (b).
Drug infusion The delivery of a drug (such as an antibiotic) through an intravenous line may be modeled by the differential equation m′ ( t ) + km ( t ) = I , where m ( t ) is the mass of the drug in the blood at time t ≥ 0, k is a constant that describes the rate at which the drug is absorbed, and I is the infusion rate. a. Show by substitution that if the initial mass of drug in the blood is zero ( m (0) = 0), then the solution of the initial value problem is m ( t ) = I k ( 1 − e − k t ) . b. Graph the solution for I = 10 mg/hr and k = 0.05 hr –1 . c. Evaluate lim t → ∞ m ( t ) , the steady-state drug level, and verify the result using the graph in part (b).
Solution Summary: The author explains that if the initial mass of the drug in the blood is zero, then satisfies the differential equation.
Drug infusion The delivery of a drug (such as an antibiotic) through an intravenous line may be modeled by the differential equation m′(t) + km(t) = I, where m(t) is the mass of the drug in the blood at time t ≥ 0, k is a constant that describes the rate at which the drug is absorbed, and I is the infusion rate.
a. Show by substitution that if the initial mass of drug in the blood is zero (m(0) = 0), then the solution of the initial value problem is
m
(
t
)
=
I
k
(
1
−
e
−
k
t
)
.
b. Graph the solution for I = 10 mg/hr and k = 0.05 hr–1.
c. Evaluate
lim
t
→
∞
m
(
t
)
, the steady-state drug level, and verify the result using the graph in part (b).
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
A body of mass m at the top of a 100 m high tower is thrown vertically upward with an initial velocity of 10 m/s. Assume that the air resistance FD acting on the body is proportional to the velocity V, so that FD=kV. Taking g = 9.75 m/s2 and k/m = 5 s, determine: a) what height the body will reach at the top of the tower, b) how long it will take the body to touch the ground, and c) the velocity of the body when it touches the ground.
A chemical reaction involving the interaction of two substances A and B to form a new compound X is called a second order reaction. In such cases it is observed that the rate of reaction (or the rate at which the new compound is formed) is proportional to the product of the remaining amounts of the two original substances. If a molecule of A and a molecule of B combine to form a molecule of X (i.e., the reaction equation is A + B ⮕ X), then the differential equation describing this specific reaction can be expressed as:
dx/dt = k(a-x)(b-x)
where k is a positive constant, a and b are the initial concentrations of the reactants A and B, respectively, and x(t) is the concentration of the new compound at any time t. Assuming that no amount of compound X is present at the start, obtain a relationship for x(t). What happens when t ⮕∞?
Consider a body of mass m dropped from rest at t = 0. The body falls under the influence of gravity, and the air resistance FD opposing the motion is assumed to be proportional to the square of the velocity, so that FD = kV2. Call x the vertical distance and take the positive direction of the x-axis downward, with origin at the initial position of the body. Obtain relationships for the velocity and position of the body as a function of time t.
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