Solve the initial-value problem: x 1 ' = − ( tan t ) x 1 + 3 cos 2 t , x 2 ' = x 1 + ( tan t ) x 2 + 2 sin t , x 1 ( 0 ) = 4 , x 2 ( 0 ) = 0 .
Solve the initial-value problem: x 1 ' = − ( tan t ) x 1 + 3 cos 2 t , x 2 ' = x 1 + ( tan t ) x 2 + 2 sin t , x 1 ( 0 ) = 4 , x 2 ( 0 ) = 0 .
Solution Summary: The author explains how to solve the initial value problem. The integrating factor of the first order differential equation is given by edisplaystyle
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