Concept explainers
a)
Interpretation:
The name of the
Concept introduction:
The longest carbon chain which contains the carbon-carbon triple bond is chosen. The chain is numbered from the end that gives the lowest number to the carbon in triple bond. Compounds with more than one triple bond are called diynes, triynes and so forth. Compounds containing both double bond and triple bonds are called as enynes. The chain is numbered from the end nearer to the first of the multiple bonds, double or triple. When there is a choice in numbering the double bond is given preference and the lowest number is given to it.
To give:
The name of the alkyne shown.
b)
Interpretation:
The name of the alkyne shown is to be given.
Concept introduction:
The longest carbon chain which contains the carbon-carbon triple bond is chosen. The chain is numbered from the end that gives the lowest number to the carbon in triple bond. Compounds with more than one triple bond are called diynes, triynes and so forth. Compounds containing both double bond and triple bonds are called as enynes. The chain is numbered from the end nearer to the first of the multiple bonds, double or triple. When there is a choice in numbering the double bond is given preference and the lowest number is given to it.
To give:
The name of the alkyne shown.
c)
Interpretation:
The name of the alkyne shown is to be given.
Concept introduction:
The longest carbon chain which contains the carbon-carbon triple bond is chosen. The chain is numbered from the end that gives the lowest number to the carbon in triple bond. Compounds with more than one triple bond are called diynes, triynes and so forth. Compounds containing both double bond and triple bonds are called as enynes. The chain is numbered from the end nearer to the first of the multiple bonds, double or triple. When there is a choice in numbering the double bond is given preference and the lowest number is given to it.
To give:
The name of the alkyne shown.
d)
Interpretation:
The name of the alkyne shown is to be given.
Concept introduction:
The longest carbon chain which contains the carbon-carbon triple bond is chosen. The chain is numbered from the end that gives the lowest number to the carbon in triple bond. Compounds with more than one triple bond are called diynes, triynes and so forth. Compounds containing both double bond and triple bonds are called as enynes. The chain is numbered from the end nearer to the first of the multiple bonds, double or triple. When there is a choice in numbering the double bond is given preference and the lowest number is assigned to it.
To give:
The name of the alkyne shown.
e)
Interpretation:
The name of the alkyne shown is to be given.
Concept introduction:
The longest carbon chain which contains the carbon-carbon triple bond is chosen. The chain is numbered from the end that gives the lowest number to the carbon in triple bond. Compounds with more than one triple bond are called diynes, triynes and so forth. Compounds containing both double bond and triple bonds are called as enynes. The chain is numbered from the end nearer to the first of the multiple bonds, double or triple. When there is a choice in numbering the double bond is given preference and the lowest number is assigned to it.
To give:
The name of the alkyne shown.
f)
Interpretation:
The name of the alkyne shown is to be given.
Concept introduction:
The longest carbon chain which contains the carbon-carbon triple bond is chosen. The chain is numbered from the end that gives the lowest number to the carbon in triple bond. Compounds with more than one triple bond are called diynes, triynes and so forth. Compounds containing both double bond and triple bonds are called as enynes. The chain is numbered from the end nearer to the first of the multiple bonds, double or triple. When there is a choice in numbering the double bond is given preference and the lowest number is assigned to it.
To give:
The name of the alkyne shown.
Trending nowThis is a popular solution!
Chapter 9 Solutions
ORGANIC CHEMISTRY W/OWL
- What is the percent ionization in a 0.260 M solution of formic acid (HCOOH) (Ka = 1.78 × 10⁻⁴)?arrow_forwardDetermine the pH of solution of HC3H5O2 By constructing an ICE table writing the equilibrium constant expression, and using this information to determine the pH. The Ka of HC3H5O2 is 1.3 x 10-5arrow_forwardDetermine if the following salt is neutral, acidic or basic. If acidic or basic, write the appropriate equilibrium equation for the acid or base that exists when the salt is dissolved in aqueous solution. If neutral, simply write only NR. Be sure to include the proper phases for all species within the reaction LiNO3arrow_forward
- An unknown weak acid with a concentration of 0.410 M has a pH of 5.600. What is the Ka of the weak acid?arrow_forward(racemic) 19.84 Using your reaction roadmaps as a guide, show how to convert 2-oxepanone and ethanol into 1-cyclopentenecarbaldehyde. You must use 2-oxepanone as the source of all carbon atoms in the target molecule. Show all reagents and all molecules synthesized along the way. & + EtOH H 2-Oxepanone 1-Cyclopentenecarbaldehydearrow_forwardR₂ R₁ R₁ a R Rg Nu R₂ Rg R₁ R R₁₂ R3 R R Nu enolate forming R₁ R B-Alkylated carbonyl species or amines Cyclic B-Ketoester R₁₁ HOB R R₁B R R₁₂ B-Hydroxy carbonyl R diester R2 R3 R₁ RB OR R₂ 0 aB-Unsaturated carbonyl NaOR Aldol HOR reaction 1) LDA 2) R-X 3) H₂O/H₂O ketone, aldehyde 1) 2°-amine 2) acid chloride 3) H₂O'/H₂O 0 O R₁ R₁ R R₁ R₁₂ Alkylated a-carbon R₁ H.C R₁ H.C Alkylated methyl ketone acetoacetic ester B-Ketoester ester R₁ HO R₂ R B-Dicarbonyl HO Alkylated carboxylic acid malonic ester Write the reagents required to bring about each reaction next to the arrows shown. Next, record any regiochemistry or stereochemistry considerations relevant to the reaction. You should also record any key aspects of the mechanism, such as forma- tion of an important intermediate, as a helpful reminder. You may want to keep track of all reactions that make carbon-carbon bonds, because these help you build large molecules from smaller fragments. This especially applies to the reactions in…arrow_forward
- When anisole is treated with excess bromine, the reaction gives a product which shows two singlets in 1H NMR. Draw the product.arrow_forward(ii) Draw a reasonable mechanism for the following reaction: CI NaOH heat OH (hint: SNAr Reaction) :arrow_forwardDraw the major product in each of the following reaction:arrow_forward
Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning