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Write a printf or scanf statement for each of the following:
- Print unsigned integer 40000 left justified in a 15-digit field with 8 digits.
- Read a hexadecimal value into variable hex.
- Print 200 with and without a sign.
- Print 100 in hexadecimal form preceded by 0x.
- Read characters into array s until the letter p is encountered.
- Print 1.234 in a 9-digit field with preceding zeros.
- Read a time of the form hh:mm:ss, storing the parts of the time in the integer variables hour, minute and second. Skip the colons (:) in the input stream. Use the assignment suppression character.
- Read a string of the form “characters” from the standard input. Store the string in character array s. Eliminate the quotation marks from the input stream.
- Read a time of the form hh:mm:ss, storing the parts of the time in the integer variables hour, minute and second. Skip the colons (:) in the input stream. Do not use the assignment suppression character.
a.
To write a printf or scanf statement for given condition.
Explanation of Solution
Given information:
Print unsigned integer 40000 left justified in a 15-digit field with 8 digits.
Explanation:
Following is the print statement to print an unsigned integer 40000 left justified in a 15-digit field with 8 digits:
printf ( “%-15.8u”,40000 ) ;
The printf displays the given number as 8 digits with left justification in a l5 digit field.
- -15 placed to the immediate right of % sign, is used to left justify the number and occupy 15 spaces.
- Digit 8 after the decimal point places zeros to the left of the number to make it an 8-digit number.
- Conversion specifier u is used to print unsigned numbers.
b.
To write a printf or scanf statement for given condition.
Explanation of Solution
Given information:
Read a hexadecimal value into variable hex.
Explanation:
Following is the scanf statement to read a hexadecimal value into hex variable:
scanf ( “%x”, hex ) ;
The scanf statement inputs a hexadecimal number in the variable named hex using conversion specifier %x.
c.
To write a printf or scanf statement for given condition.
Explanation of Solution
Given information:
Print 200 with and without a sign.
Explanation:
Following is the printf statement to print 200 with and without a sign:
printf ( “%+d\n %d\n”, 200, 200 ) ;
The printf statement prints the value 200, with and without a plus sign. If we place a + sign immediate to the right of %sign, then, a positive value is printed with a plus sign and a negative value is printed with a minus sign.
d.
To write a printf or scanf statement for given condition.
Explanation of Solution
Given information:
Print 100 in hexadecimal form preceded by 0x.
Explanation:
Following is the printf statement to print 100 in hexadecimal form preceded by 0x:
printf ( “%#x\n”, 100 ) ;
The printf statement is used to print 100 preceded by Ox. This is accomplished by using a # flag placed immediate to the right of % sign in the field.
e.
To write a printf or scanf statement for given condition.
Explanation of Solution
Given information:
Read characters into arrays s until the letter p is encountered.
Explanation:
Following is the scanf statement to read characters into arrays s until the letter p is encountered:
scanf ( “%[^p]”, s ) ;
The scanf statement is used to read the string until the letter p appears. This is achieved by inverted scan set, that is, by placing a Caret (^) before the character.
f.
To write a printf or scanf statement for given condition.
Explanation of Solution
Given information:
Print 1.234 in a 9-digit field with preceding zeros.
Explanation:
Following is the printf statement to print 1.234 in a 9-digit field with preceding zeros:
printf ( “%09.3f\n”, 1.234 ) ;
The printf statement prints the given floating-point number in the field of 9 digits and preceded by zeros. Thus achieved by placing 09 immediate to the right of % sign.
Digit 3 after the decimal point is used to provide precision up to 3 values.
g.
To write a printf or scanf statement for the given condition.
Explanation of Solution
Given information:
Write time of the hh: mm: ss type, storing the timepieces in the hour, minute and second integer variables. Skip the colons (:) through the input tube. Use the character assignment Suppression.
Explanation:
Following is the scanf statement to read the time in form hh:mm:ss -:
scanf ( “%d*c%d*c%d”, &hour, &minute, &second ) ;
The scanf statement is used to input the time in the form hh:mm:ss. The colons (:) are eliminated using the suppression character (*) in the field.
h.
To write a printf or scanf statement for given condition.
Explanation of Solution
Given information:
Read a string from the standard input of the "characters" type. Place the string in character array s. Eliminate quotation marks from the input stream.
Explanation:
Following is the scanf statement to read a string of characters and store in array s -:
scanf ( “\”%[^\“]”, s ) ;
The scanf statement is used to input a string by the in quotation marks in a character array, s, and eliminate those quotation marks.
This is achieved by using an inverted scan set where a caret (^) before the \” sign is placed.
i.
To write a printf or scanf statement for given condition.
Explanation of Solution
Given information:
Read a time of type hh: mm: ss, storing time pieces in the hour, minute and second integer variables. Skip the input stream colons (:). Do not use the character Assignment Suppression.
Explanation:
Following is the scanf statement to read the time in form hh:mm:ss and skip the colons without using assignment suppression character -:
scanf ( “%d:%d:%d: ”, &hour, &minute, &second ) ;
The scanf statement is used to input the time in the form hh:mm:ss. The colons (:) are eliminated by placing colons (:) in the scanf statement as shown, if we do not have to put suppression character.
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