(a) Interpretation: The major monobromination product that would be obtained when methylcyclohexane is treated with bromine and light is to be predicted. The explanation for the corresponding answer is to be stated. Concept introduction: Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

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Answer 1

Question

Chapter 9, Problem 9.43P

Interpretation Introduction

(a)

Interpretation:

The major monobromination product that would be obtained when methylcyclohexane is treated with bromine and light is to be predicted. The explanation for the corresponding answer is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

Interpretation Introduction

(b)

Interpretation:

The relative amounts of the three possible monochlorination product of the photochlorination of triptane is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

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Part II. two unbranched ketone have molecular formulla (C8H100). El-ms showed that both of them have a molecular ion peak at m/2 =128. However ketone (A) has a fragment peak at m/2 = 99 and 72 while ketone (B) snowed a fragment peak at m/2 = 113 and 58. 9) Propose the most plausible structures for both ketones b) Explain how you arrived at your conclusion by drawing the Structures of the distinguishing fragments for each ketone, including their fragmentation mechanisms.

Answer 2

Question

Chapter 9, Problem 9.43P

Interpretation Introduction

(a)

Interpretation:

The major monobromination product that would be obtained when methylcyclohexane is treated with bromine and light is to be predicted. The explanation for the corresponding answer is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

Interpretation Introduction

(b)

Interpretation:

The relative amounts of the three possible monochlorination product of the photochlorination of triptane is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

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Answer 3

Question

Chapter 9, Problem 9.43P

Interpretation Introduction

(a)

Interpretation:

The major monobromination product that would be obtained when methylcyclohexane is treated with bromine and light is to be predicted. The explanation for the corresponding answer is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

Interpretation Introduction

(b)

Interpretation:

The relative amounts of the three possible monochlorination product of the photochlorination of triptane is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

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Answer 4

Question

Chapter 9, Problem 9.43P

Interpretation Introduction

(a)

Interpretation:

The major monobromination product that would be obtained when methylcyclohexane is treated with bromine and light is to be predicted. The explanation for the corresponding answer is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

Interpretation Introduction

(b)

Interpretation:

The relative amounts of the three possible monochlorination product of the photochlorination of triptane is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

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Answer 5

Chapter 9, Problem 9.43P

Interpretation Introduction

(a)

Interpretation:

The major monobromination product that would be obtained when methylcyclohexane is treated with bromine and light is to be predicted. The explanation for the corresponding answer is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

Interpretation Introduction

(b)

Interpretation:

The relative amounts of the three possible monochlorination product of the photochlorination of triptane is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

Answer 6

Chapter 9, Problem 9.43P

Interpretation Introduction

(a)

Interpretation:

The major monobromination product that would be obtained when methylcyclohexane is treated with bromine and light is to be predicted. The explanation for the corresponding answer is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

Answer 7

Chapter 9, Problem 9.43P

Interpretation Introduction

(a)

Interpretation:

The major monobromination product that would be obtained when methylcyclohexane is treated with bromine and light is to be predicted. The explanation for the corresponding answer is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The relative amounts of the three possible monochlorination product of the photochlorination of triptane is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The relative amounts of the three possible monochlorination product of the photochlorination of triptane is to be stated.

Concept introduction:

Free radical halogenation of alkane is a reaction in which free radicals are generated to precede the reaction. The halogen molecule first undergoes homolytic bond cleavage to form two halogen radicals, then these halogen radicals initiate the reaction by forming alkyl radical. The reaction then further propagates.

Answer 10

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Answer 11

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Answer 13

Ch. 9 - Prob. 9.1P Ch. 9 - Prob. 9.2P Ch. 9 - Prob. 9.3P Ch. 9 - Prob. 9.4P Ch. 9 - Prob. 9.5P Ch. 9 - Prob. 9.6P Ch. 9 - Prob. 9.7P Ch. 9 - Prob. 9.8P Ch. 9 - Prob. 9.9P Ch. 9 - Prob. 9.10P

Solution Summary: The author explains that the major monobromination product of methylcyclohexane is to be predicted when it is treated with bromine and light.

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