Explanation Given info: The mass of the one block m 1 is 5.00 kg , the height through which block is released h is 5.00 m and the mass of the second block m 2 is 10.0 kg . Write the equation of conservation of total energy. K i + U i = K f + U f (1) Here, K i is the initial kinetic energy. U i is the initial potential energy. K f is the final kinetic energy. U f is the final potential energy. Initially the mass m 1 is at rest at height h due to which the initial velocity v 1i of mass m 1 is zero. So, the initial kinetic energy is zero. K i = 0 v 1i is the initial velocity of the mass m 1 . Write the equation of initial potential energy. U i = m 1 g h Here, m 1 is the mass of the first block. g is the acceleration due to gravity. h is the height of the mass m 1 . Write the equation of final kinetic energy. K f = 1 2 m 1 v 2 Here, v is the velocity of the mass m 1 just before the collision with the mass m 2 when it reaches at the bottom. When the mass m 1 reaches at the bottom then its height reduces to zero due to which the final potential energy U f is zero. U f = 0 Substitute 0 for K i , m 1 g h for U i , ( 1 2 m 1 v 2 ) for K f and 0 for U f in equation (1) to find v . 0 + m 1 g h = 1 2 m 1 v 2 + 0 v = 2 g h When a mass collide head on with another rest mass and an elastic collision occurs then the final speed of the first mass is, v 1f = ( m 1 − m 2 m 1 + m 2 ) v Here, v 1f is the final velocity of the mass m 1 . m 2 is the mass of the second block. Substitute 2 g h for v in above equation to find v 1f . v 1f = ( m 1 − m 2 m 1 + m 2 ) 2 g h The front end of mass m 1 is attached with North Pole of a strong magnet and the back end of the mass m 2 is attached with North Pole of identical magnet due to which mass m 1 repels the mass m 2 when it slides down

Bundle: Physics for Scientists and Engineers, Technology Update, 9th Loose-leaf Version + WebAssign Printed Access Card, Multi-Term

9th Edition

ISBN: 9781305714892

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Question

Chapter 9, Problem 9.33P

To determine

The maximum height through which block of mass m1 rises after the elastic collision.

Expert Solution & Answer

Chapter 9 Solutions

Bundle: Physics for Scientists and Engineers, Technology Update, 9th Loose-leaf Version + WebAssign Printed Access Card, Multi-Term

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The maximum height through which block of mass m 1 rises after the elastic collision.

Solution Summary: The author calculates the maximum height through which block of mass m_1 rises after the elastic collision.

The maximum height through which block of mass m1 rises after the elastic collision.

Chapter 9 Solutions