The main group of X in an ionic compound X 2 O 3 is to be determined. Concept introduction: An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions. In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions. The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as, Group number = 8 − ( charge present on anion ) (1)

Question

Want to see the full answer?

Answer 1

Question

Chapter 9, Problem 9.24P

(a)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound X2O3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as,

Group number=8−(charge present on anion) (1)

(b)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound XCO3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

(c)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound Na2X is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer appropriately in the box. Only the answer in the box will be graded. (3) points) OH OH بر بد بدید 2 3

There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…

A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ M

Answer 2

Question

Chapter 9, Problem 9.24P

(a)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound X2O3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as,

Group number=8−(charge present on anion) (1)

(b)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound XCO3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

(c)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound Na2X is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 9, Problem 9.24P

(a)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound X2O3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as,

Group number=8−(charge present on anion) (1)

(b)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound XCO3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

(c)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound Na2X is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 9, Problem 9.24P

(a)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound X2O3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as,

Group number=8−(charge present on anion) (1)

(b)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound XCO3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

(c)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound Na2X is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 9, Problem 9.24P

(a)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound X2O3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as,

Group number=8−(charge present on anion) (1)

(b)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound XCO3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

(c)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound Na2X is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

Answer 6

Chapter 9, Problem 9.24P

(a)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound X2O3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as,

Group number=8−(charge present on anion) (1)

Answer 7

Chapter 9, Problem 9.24P

(a)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound X2O3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as,

Group number=8−(charge present on anion) (1)

Answer 8

(b)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound XCO3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

Answer 9

(b)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound XCO3 is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

Answer 10

(c)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound Na2X is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

Answer 11

(c)

Interpretation Introduction

Interpretation:

The main group of X in an ionic compound Na2X is to be determined.

Concept introduction:

An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.

In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.

The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Group number=(charge present on anion)+8 (1)

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 9.2 - Use condensed electron configurations, partial...Ch. 9.2 - Prob. 9.1BFP Ch. 9.2 - Prob. 9.2AFP Ch. 9.2 - Prob. 9.2BFP Ch. 9.3 - Prob. 9.3AFP Ch. 9.3 - Prob. 9.3BFP Ch. 9.4 - One of the most important industrial reactions is...Ch. 9.4 - Prob. 9.4BFP Ch. 9.5 - Prob. 9.5AFP Ch. 9.5 - Prob. 9.5BFP

Concept explainers

Videos

Want to see the full answer?

Chapter 9 Solutions