Chapter 9, Problem 9.1E

Write the dissociation equations for the following that emphasize their behavior as Arrhenius acids:

a. $\text{HI}$

b. $\text{HBrO}$

c. $\text{HCN}$

d. ${\text{HClO}}_{\text{2}}$

Interpretation Introduction

(a)

Interpretation:

The dissociation equation for the given species emphasizing on its behavior as Arrhenius acid is to be stated.

Concept introduction:

According to Arrhenius theory, a substance that dissociates to give hydrogen ions $\left({\text{H}}^{\text{+}}\right)$ in the solution is known as an acid. On the other hand, a substance that dissociates to give hydroxide ions $\left({\text{OH}}^{-}\right)$ in the solution is known as base.

Answer to Problem 9.1E

The dissociation equation for the given species, $\text{HI}$, emphasizing on its behavior as Arrhenius acid is given below as,

$\text{HI}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{Cl}}^{-}\left(\text{aq}\right)$.

Explanation of Solution

The given species is $\text{HI}$. On dissolving $\text{HI}$ in water, it dissociates into its ions. The equation for its dissociation in the solution is given as follows.

$\text{HI}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{Cl}}^{-}\left(\text{aq}\right)$

In the above reaction, $\text{HI}$ dissociates to give hydrogen ions $\left({\text{H}}^{\text{+}}\right)$ in the solution. Therefore, according to Arrhenius theory, it is an acid.

Conclusion

The dissociation equation for the given species, $\text{HI}$, emphasizing on its behavior as Arrhenius acid is given below as,

$\text{HI}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{Cl}}^{-}\left(\text{aq}\right)$.

Interpretation Introduction

(b)

Interpretation:

The dissociation equation for the given species emphasizing on its behavior as Arrhenius acid is to be stated.

Concept introduction:

According to Arrhenius theory, a substance that dissociates to give hydrogen ions $\left({\text{H}}^{\text{+}}\right)$ in the solution is known as an acid. On the other hand, a substance that dissociates to give hydroxide ions $\left({\text{OH}}^{-}\right)$ in the solution is known as base.

Answer to Problem 9.1E

The dissociation equation for the given species, $\text{HBrO}$, emphasizing on its behavior as Arrhenius acid is given below as,

$\text{HBrO}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{BrO}}^{-}\left(\text{aq}\right)$.

Explanation of Solution

The given species is $\text{HBrO}$. On dissolving $\text{HBrO}$ in water, it dissociates into its ions. The equation for its dissociation in the solution is given as follows.

$\text{HBrO}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{BrO}}^{-}\left(\text{aq}\right)$

In the above reaction, $\text{HBrO}$ dissociates to give hydrogen ions $\left({\text{H}}^{\text{+}}\right)$ in the solution. Therefore, according to Arrhenius theory, it is an acid.

Conclusion

The dissociation equation for the given species, $\text{HBrO}$, emphasizing on its behavior as Arrhenius acid is given below as,

$\text{HBrO}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{BrO}}^{-}\left(\text{aq}\right)$.

Interpretation Introduction

(c)

Interpretation:

The dissociation equation for the given species emphasizing on its behavior as Arrhenius acid is to be stated.

Concept introduction:

According to Arrhenius theory, a substance that dissociates to give hydrogen ions $\left({\text{H}}^{\text{+}}\right)$ in the solution is known as an acid. On the other hand, a substance that dissociates to give hydroxide ions $\left({\text{OH}}^{-}\right)$ in the solution is known as base.

Answer to Problem 9.1E

The dissociation equation for the given species, $\text{HCN}$, emphasizing on its behavior as Arrhenius acid is given below as,

$\text{HCN}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{CN}}^{-}\left(\text{aq}\right)$.

Explanation of Solution

The given species is $\text{HCN}$. On dissolving $\text{HCN}$ in water, it dissociates into its ions. The equation for its dissociation in the solution is given as follows.

$\text{HCN}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{CN}}^{-}\left(\text{aq}\right)$

In the above reaction, $\text{HCN}$ dissociates to give hydrogen ions $\left({\text{H}}^{\text{+}}\right)$ in the solution. Therefore, according to Arrhenius theory, it is an acid.

Conclusion

The dissociation equation for the given species, $\text{HCN}$, emphasizing on its behavior as Arrhenius acid is given below as,

$\text{HCN}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{CN}}^{-}\left(\text{aq}\right)$.

Interpretation Introduction

(d)

Interpretation:

The dissociation equation for the given species emphasizing on its behavior as Arrhenius acid is to be stated.

Concept introduction:

According to Arrhenius theory, a substance that dissociates to give hydrogen ions $\left({\text{H}}^{\text{+}}\right)$ in the solution is known as an acid. On the other hand, a substance that dissociates to give hydroxide ions $\left({\text{OH}}^{-}\right)$ in the solution is known as base.

Answer to Problem 9.1E

The dissociation equation for the given species, ${\text{HClO}}_{\text{2}}$, emphasizing on its behavior as Arrhenius acid is given below as,

${\text{HClO}}_{\text{2}}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{ClO}}_2^{-}\left(\text{aq}\right)$.

Explanation of Solution

The given species is ${\text{HClO}}_{\text{2}}$. On dissolving ${\text{HClO}}_{\text{2}}$ in water, it dissociates into its ions. The equation for its dissociation in the solution is given as follows.

${\text{HClO}}_{\text{2}}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{ClO}}_2^{-}\left(\text{aq}\right)$

In the above reaction, ${\text{HClO}}_{\text{2}}$ dissociates to give hydrogen ions $\left({\text{H}}^{\text{+}}\right)$ in the solution. Therefore, according to Arrhenius theory, it is an acid.

Conclusion

The dissociation equation for the given species, ${\text{HClO}}_{\text{2}}$, emphasizing on its behavior as Arrhenius acid is given below as,

${\text{HClO}}_{\text{2}}\left(\text{aq}\right)\to {\text{H}}^{\text{+}}\left(\text{aq}\right)+{\text{ClO}}_2^{-}\left(\text{aq}\right)$.