Chapter 9, Problem 9.17P

Don't use ai to answer I will report you answer

BW=1MHZ For Johnson-Nyquist Noise Generator (or Thermal Noise Generator), the device utilizes the thermal noise that naturally arises from the random motion of electrons in resistors at a non-zero temperature. The voltage is arising from thermal noise in two resistors of 80 and 120 Qat Temperature T=290 °k: 1-Write the equations of v(t), 12(t), up on the circuit diagram of series and parallel connecti 2- Apply the equation v(t) to find Vrms for series connection scheme. 3- Find inrms for Series scheme 4- Find the Vrms for series scheme. By using i̟rms √³(+)O v²(t) 80 120 ww R₁ R₂ Gi G if(t) 1/80 1/120

For Johnson-Nyquist Noise Generator (or Thermal Noise Generator), the device utilizes the thermal noise that naturally arises from the random motion of electrons in resistors at a non-zero temperature. The voltage is arising from thermal noise in two resistors of 80 and 120 Qat Temperature T=290 °k: 1-Write the equations of v(t), 12(t), up on the circuit diagram of series and parallel connecti 2- Apply the equation v(t) to find Vrms for series connection scheme. 3- Find inrms for parallel scheme 4- Find the Vrms for series scheme. By using inrms 80 Q 120 ww R₁ R₂ v²(t) Gi i²(t) 1/80 1/120

Vcc=-12 V；R1=33 kΩ；RC=1.8 kΩ；βDC = 150；RE=560Ω；R2=5.6 k Ω確定圖5-38中的I1、I2和IB。 課本給的答案A: I1=315μA；I2=288μA ；IB=27μA，請教我計算過程

Consider the following circuit, assuming the switch has been in the same position for a long period of time before t = 0: Vx L iL R3 R2 R₁ Is + Vo - コロ >Where Is = 100 mA,R=2202, R2 = 4702,R3 =4702,L= 1 mH. As indicated on the diagram, before t = 0, the switch is closed, after t = 0 the switch is open. 1. What are Ve and Vo before the switch shown opens (answer to within 1% accuracy)? Vx = V, Vo = V 2. What is the T of the RL circuit after the switch operates (answer to within 1% accuracy)? T= μs 3. Complete the derivation for the inductor current in (t) differential equation below by filling in the blank coefficients (answer to within 1% accuracy): diy(1) dt di (0) + iz (t)+ = 0 4. Hence or otherwise, find the time domain expression for Vo(t) (answer to within 1% accuracy): Vo(t)= exp(

確定圖5-38中的I1、I2和IB。 Vcc=-12 V；R1=33 kN；RC=1.8 kN；βDC = 150；RE=560；R2=5.6 kN  圖 5-38

Consider the following circuit: Vs R₁ Vx ww C'₁ R2 Where Vs = 3.3 cos(2000t-10) VR:=2202 R2 = 1002,L=1mH, Ci = 22 nF, C2 = 47 nF N.B. We have been using cosine as the basis for our phasors. 1. What is the impedance of each of R, Ci, L (answer to within 1%): Z RI = +j Q Zci= +j QZL= +jQ 心 2. Complete the following KCL for node Vo, assuming current flowing out of the node is positive (answer to within 1%): 0= +j )+Vo/ +j0)+Vo/(0+j 回回回 3. Hence or otherwise solve for Vo in phasor form (answer to within 1% amplitude and 5 degrees of phase): Vo = ° V 回 4. Convert this phasor to a time domain expression for Vo(t) (answer to within 1% amplitude and 5 degrees of phase): Vo(t) = cos( t+ Vo 1

is pf leading, lagging or neither?

*please use pen and paper to show work (thank you!!!)* Design a synchronous binary up-counter using 4 negative edge-triggered JK flip-flops provided with a clock. The states (sequences) 1100, 1001 and 1000 are considered as unused states. (i)  Draw the state diagram of the counter. (ii)  Build the counter’s state table showing the synchronous inputs of the JK flip-flops as well. (iii)  Using Karnaugh-maps, find the minimal sum-of-products (SOP) form of the equations for the inputs to the flip-flops; assume the next states of the unused combinations to be <don’t care states=. (iv)  Draw the logic circuit of the counter.