Chapter 9, Problem 9.17E

(a)

Interpretation Introduction

Interpretation:

The name and the formula of the compound formed when $\text{0}\text{.0010}\text{mol}$ of ${\text{CoCl}}_{\text{3}}{\text{.5NH}}_{\text{3}}{\text{.H}}_{\text{2}}\text{O}$ reacts with an excess of silver chloride have to be given.

Concept Introduction:

Hydrate Isomers:

Hydrate isomers differ by the exchange of a ${\text{H}}_{\text{2}}\text{O}$ molecule with another ligand in the coordination sphere.  It can be distinguished by the stoichiometry of reactions in which the ion is exchanged with water.

Example:

2 mole of $\text{AgCl}$ can be precipitated from 1 mole $\left[{\text{CrCl(OH}}_{\text{2}}{\text{)}}_{\text{5}}\right]{\text{Cl}}_{\text{2}}{\text{.H}}_{\text{2}}\text{O}\text{.}$

  $\left[{\text{CrCl(OH}}_{\text{2}}{\text{)}}_{\text{5}}\right]{\text{Cl}}_{\text{2}}{\text{.H}}_{\text{2}}{\text{O+2Ag}}^{\text{+}}\stackrel{}{\to }\left[{\text{CrCl(OH}}_{\text{2}}{\text{)}}_{\text{5}}\right]{\text{H}}_{\text{2}}\text{O+2AgCl}$

(b)

Interpretation Introduction

Interpretation:

The name and the formula of the compound formed when $\text{0}\text{.0010}\text{mol}$ of the complex ${\text{CoCl}}_{\text{3}}{\text{.5NH}}_{\text{3}}$ is reacts with an excess of silver nitrate have to be given.

Concept Introduction:

Refer to part (a).