Explanation We have, 4 N H 3 + 5 O 2 → 4 N O + 6 H 2 O For one mole the reaction is divided by 4 as follows: N H 3 + 5 4 O 2 → N O + 3 2 H 2 O Now, Δ H 0 for the reaction is obtained by given formula: Δ H 0 r x n = Δ H 0 p r o d u c t − Δ H 0 r e a c tan t s Add the heat of formation of all the reactants and products and subtract them together. The pure elements have no heat of formation

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Chapter 9, Problem 9.15P

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To determine:

The heat of reaction ΔH0 for the reaction of ammonia with O₂ gas to yield NO and H₂O(g).

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Chapter 9, Problem 9.14A

Chapter 9, Problem 9.16A

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The heat of reaction Δ H 0 for the reaction of ammonia with O 2 gas to yield NO and H 2 O(g).

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To determine: The heat of reaction ΔH0 for the reaction of ammonia with O2 gas to yield NO and H2O(g).

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Chapter 9 Solutions

To determine:

The heat of reaction ΔH0 for the reaction of ammonia with O₂ gas to yield NO and H₂O(g).