Principles of Foundation Engineering, SI Edition
9th Edition
ISBN: 9781337672085
Author: Das, Braja M., SIVAKUGAN, Nagaratnam
Publisher: Cengage Learning
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Question
Chapter 9, Problem 9.14P
To determine
Find the elastic settlement using Burland and Burbidge’s method.
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Question 1) For a shallow foundation measuring (1.7 m x 2.2 m) as shown below: ,
A. Estimate the elastic settlement proposed by Mayerhof. Then,
B. Estimate the elastic settlement proposed by Bowles, if the water table rises 1.5 m. Then,
Use yw=10 kN/m³
qnet= 1.2 MN/m2
G.S
1.5 m
Sand
Yd=16 kN/m³ Ysat= 17 kN/m3
%3D
2.5 m
N60=52
V W.T.
Silty Sand Ya=18 kN/m³ Ysat = 18.5 kN/m?
N60=52
3.5 m
Sand
Ya=19 kN/m3
Ysat = 22 kN/m³
e, = 0.4, Ae=0.04 , o'= 194 kN/m2
5 m
Cc= 0.3, Cs= 0.2 , Ca= 0.05 N60=60
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Please solve this detailed step by step
10. A flexible foundation is subjected to a uniformly distributed load of q-500 kN/m². Table 3
could be useful. Determine the increase in vertical stress, in kPa, Aoz at a depth of z=3m under
point F.
B
4m
3m
6m
E
10m
Table 10.3 Variation of I, with m and n
m
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1.0
0.1
0.0047 0.0092
0.0270
0.0279
0.2
0.0132
0.0092 0.0179 0.0259
0.0132 0.0259 0.0374
0.0222 0.0242
0.0435 0.0474
0.0629 0.0686
0.0258
0.0504 0.0528
0.0547
0.3
0.0731 0.0766
0.0794
0.4
0.1013
0.5
0.0198 0.0387
0.1202
0.6 0.0222 0.0435
0.7 0.0242 0.0474
0.0947 0.1069 0.1168
0.1247 0.1311
0.1361
0.1365 0.1436
0.1491
0.1537
0.1598
0.0168 0.0198
0.0328 0.0387
0.0474 0.0559
0.0168 0.0328 0.0474 0.0602 0.0711 0.0801 0.0873 0.0931 0.0977
0.0559 0.0711 0.0840 0.0947 0.1034 0.1104 0.1158
0.0629 0.0801
0.0686 0.0873 0.1034
0.8 0.0258 0.0504 0.0731 0.0931 0.1104
0.9 0.0270 0.0528 0.0766 0.0977 0.1158
0.0794 0.1013 0.1202
0.0832
0.1263
1.4
0.1300
1.6 0.0306 0.0599 0.0871 0.1114 0.1324
1.8 0.0309 0.0606…
Chapter 9 Solutions
Principles of Foundation Engineering, SI Edition
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Similar questions
- Following are the results of a standard penetration test in the field (sandy soil): Depth (m) Field value of N60 1.5 3.0 12 4.5 11 6.0 7.5 13 9.0 11 10.5 13 Estimate the net allowable bearing capacity of a mat foundation 6.5 m x 5.0 m in plan. Here, Df = 1.5 m , and allowable settlement 50 mm. Assume that the unit weight of soil (v) = 16.5 KN/m³ Select one: O a. 30.23 kN/m2 O b. 365.86 kN/m² c. 302.3 kN/m2 O d. 302.3 N/marrow_forwardH.W 2.pdf > H.Q 6 A flexible foundation measuring 1.5 m x 3 m is supported by a saturated clay. Given: Dr = 1.2 m, H = 3 m, Es (clay)= 600 kN/m2, and qo = 150 kN/m?. Determine the average elastic settlement of the foundation. H.O 7 Figure 7.3 shows a foundation of 10 ft x 6.25 ft resting on a sand deposit. The net load per unit area at the level of the foundation, qo, is 3000 Ib/ft?. For the sand, u, = 0.3, Es = 3200 Ib/in?, Df = 2.5 ft, and H = 32 ft. Assume that the foundation is rigid and determine the elastic settlement the foundation would undergo. H.O 8 Determine the net ultimate bearing capacity of mat foundations with the following characteristics: c, = 2500 Ib/ft, = 0, B = 20 ft, L = 30 ft, D, = 6.2 ft Foundation Engineering I H.W 2 H.O 9 A 20-m-long concrete pile is shown in Figure below. Estimate the ultimate point load Q, by a. Meyerhof's method b. Coyle and Castello's method Concrete pile 460 mm x 460 mm Loose sand 20m y I86 ANi Dee s H.O 10 A concrete pile 20 m long…arrow_forwardIgnoring the given Es-data and considering that the supporting soil is clean, normally consolidated sand with the following available data:arrow_forward
- Solve Problem 7.8 using Eq. (7.29). Ignore the post-construction settlement. 7.8 Solve Problem 7.4 with Eq. (7.20). Ignore the correction factor for creep. For the unit weight of soil, use γ = 115 lb/ft3. 7.4 Figure 7.3 shows a foundation of 10 ft × 6.25 ft resting on a sand deposit. The net load per unit area at the level of the foundation, qo, is 3000 lb/ft2. For the sand, μs = 0.3, Es = 3200 lb/in.2, Df = 2.5 ft, and H = 32 ft. Assume that the foundation is rigid and determine the elastic settlement the foundation would undergo. Use Eqs. (7.4) and (7.12).arrow_forwardS1arrow_forwardplease solve th problem clearlyarrow_forward
- Question attachedarrow_forwardA square shallow foundation (B × B) is planned to be constructed on a normality consolidated (NC) clay soil as shown in the below figure. The maximum acceptable settlement for the foundation is equal to 2.0 inches (5 cm), and the safety factor against bearing capacity is FS = 4. Determine the size of foundation. (Note: To simplify the calculations, ignore both the elastic settlement and secondary compression settlement. Also consider 4o'ave = 40'm) Q = 500 kN Ysat = 19.24 kN/m³ en = 0.8 C. = 0.25 p'= 0 c'= 25 kPa 2 m B ×B FS again Bearing Capacity = 4 Acceptable settlement = 2.0 inches 10 marrow_forwardA square shallow foundation (B × B) is planned to be constructed on a normality consolidated (NC) clay soil as shown in the below figure. The maximum acceptable settlement for the foundation is equal to 2.0 inches (5 cm), and the safety factor against bearing capacity is FS = 4. Determine the size of foundation. (Note: To simplify the calculations, ignore both the elastic settlement and secondary compression settlement. Also consider Ao'ave = 4o'm) Q = 500 kN Ysat = 19.24 kN/m³ eo = 0.8 C. = 0.25 p'= 0 c' = 25 kPa FS again Bearing Capacity = 4 Acceptable settlement = 2.0 inches 2 m В ХВ 10 marrow_forward
- A square column foundation is to be constructed on a sand deposit (C = 0). The allowable load Q will be inclined at an angle bØ = 20° with the vertical. Knowing that y = 16.5 KN/ m3 and Df = 1 m. The standard Penetration numbers N60 obtained from the field are as follows. Determine value of Fqd ? Depth (m) W60 1.5 3 3.0 16 4.5 6.0 10 7.5 10 B- 1.25 m- Select one: a. 1.162 b. 11.62 c. 1.231 O d. 31.12arrow_forwardA square column foundation is to be constructed on a sand deposit (C = 0). The allowable load Q will be inclined at an angle b Ø = 20° with the vertical. Knowing that y = 16.5 KN/ m3 and Df = 1 m. The standard Penetration numbers N60 obtained from the field are as follows. Determine value of Q ? Depth (m) N60 1.5 3 3.0 6 4.5 6.0 10 7.5 10 B- 1.25 m- Select one: a. 110 KN O b. 151.7 KN c. 95 KN d. 155.3 KNarrow_forwardSolve Problem 5.6 using Eq. (5.11).arrow_forward
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