CHEM:ATOM FOC 2E CL (TEXT)
CHEM:ATOM FOC 2E CL (TEXT)
2nd Edition
ISBN: 9780393284218
Author: Stacey Lowery Bretz, Natalie Foster, Thomas R. Gilbert, Rein V. Kirss
Publisher: WW Norton & Co
Question
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Chapter 9, Problem 9.122QA
Interpretation Introduction

To calculate:

The value of the Hrxno for the overall reaction.

Expert Solution & Answer
Check Mark

Answer to Problem 9.122QA

Solution:

The value of the overall reaction,Hrxno=-1388 kJ.

Explanation of Solution

1) Concept:

We can manipulate the three equations algebraically for which Hrxno values are known so that they sum to give the equation for which Hrxno is unknown. Then by applying Hess’s law, we can calculate the unknown value.

2) Given:

We are given three reactions with their Hrxno values:

Equation (1)          NiSO3sNiO(s)+ SO2(g)        Hrxno=156 kJ     

Equation (2)          18S8(s)+ O2(g) SO2(g)            Hrxno=-297 kJ

Equation (3)         Ni s+12 O2g NiO(s)            Hrxno=-241 kJ

One reaction with unknown Hrxno value:

Equation (4)     2 Ni (s)+   14 S8(s)+3 O2(g) 2  NiSO3(s)

3)  Calculations:

We have to manipulate equations (1), (2), and (3) to get equation (4). In equation (4),  NiSO3  is on the products’ side, and in equation (1), it is on the reactants’ side, so we have to reverse equation (1). Also we have to multiply (1) by 2 because in equation (4), there are 2  NiSO3,  and in equation (1), there is only one  NiSO3 .

2 NiO (s)+2 SO2g 2 NiSO3(s)        2×-Hrxno=-312 kJ  

Now, in equation (4), there are  14S8 , and in equation (2), there are  18S8, so we have to multiply equation (2) by 2 to get  14S8  on the reactants’ side.

14S8(s)+ 2 O2(g)2 SO2(g)          2×Hrxno=-594 kJ

In equation (4), there are 2 Ni,  and in equation (3), there is only one Ni,  so we have to multiply equation (3) by 2 to get 2 Ni  on the reactants’ side.

2 Ni s+ O2g 2NiO(s)           2×Hrxno=-482 kJ

Adding all three equations, we get

2 NiO2 (s)+2 SO2 (g) 2 NiSO3 (s)           2×-Hrxno=-312 kJ  

14S8 (s)+ 2 O2 (g)2 SO2 g                               2×Hrxno=-594 Kj

2 Ni(s)+ O2 (g) 2 NiO2 s                                 2×Hrxno=-482 kJ

__________________________________________________________ 

2 Ni(s)+   14 S8 (s)+3  O2 (g) 2  NiSO3 (s)             Hrxno=-1388 kJ

The value of Hrxnois -1388 kJ.

Conclusion:

We calculated the unknown value of  Hrxno by manipulating the reactions and by using Hess’s law.

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Chapter 9 Solutions

CHEM:ATOM FOC 2E CL (TEXT)

Ch. 9 - Prob. 9.11QACh. 9 - Prob. 9.12QACh. 9 - Prob. 9.13QACh. 9 - Prob. 9.14QACh. 9 - Prob. 9.15QACh. 9 - Prob. 9.16QACh. 9 - Prob. 9.17QACh. 9 - Prob. 9.18QACh. 9 - Prob. 9.19QACh. 9 - Prob. 9.20QACh. 9 - Prob. 9.21QACh. 9 - Prob. 9.22QACh. 9 - Prob. 9.23QACh. 9 - Prob. 9.24QACh. 9 - Prob. 9.25QACh. 9 - Prob. 9.26QACh. 9 - Prob. 9.27QACh. 9 - Prob. 9.28QACh. 9 - Prob. 9.29QACh. 9 - Prob. 9.30QACh. 9 - Prob. 9.31QACh. 9 - Prob. 9.32QACh. 9 - Prob. 9.33QACh. 9 - Prob. 9.34QACh. 9 - Prob. 9.35QACh. 9 - Prob. 9.36QACh. 9 - Prob. 9.37QACh. 9 - Prob. 9.38QACh. 9 - Prob. 9.39QACh. 9 - Prob. 9.40QACh. 9 - Prob. 9.41QACh. 9 - Prob. 9.42QACh. 9 - Prob. 9.43QACh. 9 - Prob. 9.44QACh. 9 - Prob. 9.45QACh. 9 - Prob. 9.46QACh. 9 - Prob. 9.47QACh. 9 - Prob. 9.48QACh. 9 - Prob. 9.49QACh. 9 - Prob. 9.50QACh. 9 - Prob. 9.51QACh. 9 - Prob. 9.52QACh. 9 - Prob. 9.53QACh. 9 - Prob. 9.54QACh. 9 - Prob. 9.55QACh. 9 - Prob. 9.56QACh. 9 - Prob. 9.57QACh. 9 - Prob. 9.58QACh. 9 - Prob. 9.59QACh. 9 - Prob. 9.60QACh. 9 - Prob. 9.61QACh. 9 - Prob. 9.62QACh. 9 - Prob. 9.63QACh. 9 - Prob. 9.64QACh. 9 - Prob. 9.65QACh. 9 - Prob. 9.66QACh. 9 - Prob. 9.67QACh. 9 - Prob. 9.68QACh. 9 - Prob. 9.69QACh. 9 - Prob. 9.70QACh. 9 - Prob. 9.71QACh. 9 - Prob. 9.72QACh. 9 - Prob. 9.73QACh. 9 - Prob. 9.74QACh. 9 - Prob. 9.75QACh. 9 - Prob. 9.76QACh. 9 - Prob. 9.77QACh. 9 - Prob. 9.78QACh. 9 - Prob. 9.79QACh. 9 - Prob. 9.80QACh. 9 - Prob. 9.81QACh. 9 - Prob. 9.82QACh. 9 - Prob. 9.83QACh. 9 - Prob. 9.84QACh. 9 - Prob. 9.85QACh. 9 - Prob. 9.86QACh. 9 - Prob. 9.87QACh. 9 - Prob. 9.88QACh. 9 - Prob. 9.89QACh. 9 - Prob. 9.90QACh. 9 - Prob. 9.91QACh. 9 - Prob. 9.92QACh. 9 - Prob. 9.93QACh. 9 - Prob. 9.94QACh. 9 - Prob. 9.95QACh. 9 - Prob. 9.96QACh. 9 - Prob. 9.97QACh. 9 - Prob. 9.98QACh. 9 - Prob. 9.99QACh. 9 - Prob. 9.100QACh. 9 - Prob. 9.101QACh. 9 - Prob. 9.102QACh. 9 - Prob. 9.103QACh. 9 - Prob. 9.104QACh. 9 - Prob. 9.105QACh. 9 - Prob. 9.106QACh. 9 - Prob. 9.107QACh. 9 - Prob. 9.108QACh. 9 - Prob. 9.109QACh. 9 - Prob. 9.110QACh. 9 - Prob. 9.111QACh. 9 - Prob. 9.112QACh. 9 - Prob. 9.113QACh. 9 - Prob. 9.114QACh. 9 - Prob. 9.115QACh. 9 - Prob. 9.116QACh. 9 - Prob. 9.117QACh. 9 - Prob. 9.118QACh. 9 - Prob. 9.119QACh. 9 - Prob. 9.120QACh. 9 - Prob. 9.121QACh. 9 - Prob. 9.122QACh. 9 - Prob. 9.123QACh. 9 - Prob. 9.124QACh. 9 - Prob. 9.125QACh. 9 - Prob. 9.126QACh. 9 - Prob. 9.127QACh. 9 - Prob. 9.128QACh. 9 - Prob. 9.129QACh. 9 - Prob. 9.130QA
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