What are the other two reasons for choosing (b) in Example 9.7? Example 9.7 Formaldehyde (CH 2 O), a liquid with a disagreeable odor, traditionally has been used to preserve laboratory specimens. Draw the most likely Lewis structure for the compound. Strategy A plausible Lewis structure should satisfy the octet rule for all the elements, except H, and have the formal charges (if any) distributed according to electronegativity guidelines. Solution The two possible skeletal structures are First we draw the Lewis structures for each of these possibilities: To show the formal charges, we follow the procedure given in Example 9.6. In (a) the C atom has a total of five electrons (one lone pair plus three electrons from the breaking of a single and a double bond). Because C has four valence electrons, the formal charge on the atom is 4 − 5 = −1. The O atom has a total of five electrons (one lone pair and three electrons from the breaking of a single and a double bond). Because O has six valence electrons, the formal charge on the atom is 6 − 5 = +1. In (b) the C atom has a total of four electrons from the breaking of two single bonds and a double bond, so its formal charge is 4 − 4 = 0. The O atom has a total of six electrons (two lone pairs and two electrons from the breaking of the double bond). Therefore, the formal charge on the atom is 6 − 6 = 0. Although both structures satisfy the octet rule, (b) is the more likely structure because it carries no formal charges. Check In each case make sure that the total number of valence electrons is 12. Can you suggest two other reasons why (a) is less plausible?
What are the other two reasons for choosing (b) in Example 9.7? Example 9.7 Formaldehyde (CH 2 O), a liquid with a disagreeable odor, traditionally has been used to preserve laboratory specimens. Draw the most likely Lewis structure for the compound. Strategy A plausible Lewis structure should satisfy the octet rule for all the elements, except H, and have the formal charges (if any) distributed according to electronegativity guidelines. Solution The two possible skeletal structures are First we draw the Lewis structures for each of these possibilities: To show the formal charges, we follow the procedure given in Example 9.6. In (a) the C atom has a total of five electrons (one lone pair plus three electrons from the breaking of a single and a double bond). Because C has four valence electrons, the formal charge on the atom is 4 − 5 = −1. The O atom has a total of five electrons (one lone pair and three electrons from the breaking of a single and a double bond). Because O has six valence electrons, the formal charge on the atom is 6 − 5 = +1. In (b) the C atom has a total of four electrons from the breaking of two single bonds and a double bond, so its formal charge is 4 − 4 = 0. The O atom has a total of six electrons (two lone pairs and two electrons from the breaking of the double bond). Therefore, the formal charge on the atom is 6 − 6 = 0. Although both structures satisfy the octet rule, (b) is the more likely structure because it carries no formal charges. Check In each case make sure that the total number of valence electrons is 12. Can you suggest two other reasons why (a) is less plausible?
Solution Summary: The author explains the two Lewis structures for formaldehyde labelled as ‘a’ and ‘b’ in example 9.7 of the book.
What are the other two reasons for choosing (b) in Example 9.7?
Example 9.7
Formaldehyde (CH2O), a liquid with a disagreeable odor, traditionally has been used to preserve laboratory specimens. Draw the most likely Lewis structure for the compound.
Strategy A plausible Lewis structure should satisfy the octet rule for all the elements, except H, and have the formal charges (if any) distributed according to electronegativity guidelines.
Solution The two possible skeletal structures are
First we draw the Lewis structures for each of these possibilities:
To show the formal charges, we follow the procedure given in Example 9.6. In (a) the C atom has a total of five electrons (one lone pair plus three electrons from the breaking of a single and a double bond). Because C has four valence electrons, the formal charge on the atom is 4 − 5 = −1. The O atom has a total of five electrons (one lone pair and three electrons from the breaking of a single and a double bond). Because O has six valence electrons, the formal charge on the atom is 6 − 5 = +1. In (b) the C atom has a total of four electrons from the breaking of two single bonds and a double bond, so its formal charge is 4 − 4 = 0. The O atom has a total of six electrons (two lone pairs and two electrons from the breaking of the double bond). Therefore, the formal charge on the atom is 6 − 6 = 0. Although both structures satisfy the octet rule, (b) is the more likely structure because it carries no formal charges.
Check In each case make sure that the total number of valence electrons is 12. Can you suggest two other reasons why (a) is less plausible?
3)
The molecule diphosphorus tetraoxide (P,O,) has two central atoms and four different resonance
structures that do not violate the octet rule. Draw two of these resonance structures below.
4)
The compound acetone is a common solvent. It has a chemical formula of CH,COCH, Acetone has
three central atoms.
(a) Draw the Lewis Dot structure for acetone.
(b) Give the Ideal Bond Angle for all three central atoms.
5)
Four covalent molecules are drawn below.
:o:
H.
H-CH
H
H
(1)
(2)
(3)
(4)
a)
Define each of these molecules as polar or non-polar.
(1)
(2)
(3)
b)
Describe the type of intermolecular force that each molecule would use:
(1)
(2)
(3)
(4)
Labels on household cleansers caution against mixing bleach with ammonia because the reaction produces monochloramine (NH2Cl) and hydrazine (N2H4), both of which are toxic. The balanced equations are shown below.
Draw the Lewis structure for monochloramine, which is a covalent compound with the formula NH2Cl. Include all nonbonding electrons, such as lone pairs, and any nonzero formal charges.
Draw the Lewis structure for hydrazine, which has the formula N2H4. Include all nonbonding electrons, such as lone pairs, and any nonzero formal charges.
Consider the formate ion, HCO2-,
which is the anion formed when
formic acid lose an H+ ion. The H and
the two O atoms are bonded to the
central C atom.
a) Draw the best Lewis structure for
this ion.
b) Are resonance structures needed
to describe this structure?
c) Would you predict that the C-O
bond lengths in the formate ion
would be longer or shorter relative to
those in CO2?
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell