Chapter 9, Problem 8QAP

Interpretation Introduction

Interpretation:

Why 2 g of Na reacting with 1 g of ${\text{Cl}}_{\text{2}}$ not gives 2 g of NaCl should be explained.

Concept Introduction:

The combination reaction of sodium metal and chlorine gas is as follows:

  $2\text{Na}\left(s\right)+{\text{Cl}}_2\left(g\right)\to 2\text{NaCl}\left(s\right)$

From the above reaction 2 moles of sodium reacts with 1 mole of chlorine has to form 2 moles of sodium chloride. To calculate the mass of sodium chloride formed, number of moles of sodium chloride should be calculated from number of moles of reactants in the chemical reaction.