Explanation For the reaction, O H . ( g ) + C F 2 C l 2 ( g ) → H O F ( g ) + C F C l 2 . ( g ) Here, we need to break one O – H bond, two C – F bonds, and two C – C l bonds in the reactant, and we need to form one O – H bond, one O – F bond, one C – F bond, and two C – C l bonds. Δ H rxn = ∑ Δ H reactants ( bonds broken ) + ∑ Δ H products ( bonds formed ) = ∑ 1 × Δ H ( O-H ) + 2 × Δ H ( C-F ) + 2 × Δ H ( C-Cl ) + ∑ Δ H ( O-H ) + Δ H ( O-F ) + 2 × Δ H ( C-Cl )

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Chapter 9, Problem 84E

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To explain: Why the given reaction is improbable.

OH.(g) + CF2Cl2(g) → HOF(g) + CFCl2.(g)

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Chapter 9, Problem 83E

Chapter 9, Problem 85E

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Modified Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Chemistry: A Molecular Approach (4th Edition)

Ch. 9 - Prob. 1SAQ Ch. 9 - Q2. Which set of elements is arranged in order of...Ch. 9 - Q3. Which is the correct Lewis structure for...Ch. 9 - Q4. Which compound is likely to have an incomplete...Ch. 9 - Prob. 5SAQ Ch. 9 - Prob. 6SAQ Ch. 9 - Prob. 7SAQ Ch. 9 - Prob. 8SAQ Ch. 9 - Prob. 9SAQ Ch. 9 - Prob. 10SAQ

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Why the given reaction is improbable. O H . ( g ) + C F 2 C l 2 ( g ) → H O F ( g ) + C F C l 2 . ( g )

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To explain: Why the given reaction is improbable. OH.(g) + CF2Cl2(g) → HOF(g) + CFCl2.(g)

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Chapter 9 Solutions

To explain: Why the given reaction is improbable.

OH.(g) + CF2Cl2(g) → HOF(g) + CFCl2.(g)