The detailed mechanism for the formation of fluorenone from fluorene should be written. Also, the purpose of the phase −transfer-catalyst should be explained. Concept introduction: The phase-transfer-catalyst is a catalyst that helps in the migration of the reactant molecules from one phase to another. It is a special kind of heterogeneous catalyst. Phase-transfer-catalyst is used in green chemistry, asymmetric alkylations, and in the preparation of polyester polymers. Crown ethers, ammonium, and phosphonium salts are some examples of phase-transfer-catalysts.

Question

Want to see the full answer?

Answer 1

Question

Chapter 9, Problem 6Q

Interpretation Introduction

Interpretation:

The detailed mechanism for the formation of fluorenone from fluorene should be written. Also, the purpose of the phase −transfer-catalyst should be explained.

Concept introduction:

The phase-transfer-catalyst is a catalyst that helps in the migration of the reactant molecules from one phase to another. It is a special kind of heterogeneous catalyst. Phase-transfer-catalyst is used in green chemistry, asymmetric alkylations, and in the preparation of polyester polymers. Crown ethers, ammonium, and phosphonium salts are some examples of phase-transfer-catalysts.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Some of the theories used to describe interface structure can be distinguished by:1. the measured potential difference.2. the distribution of ions in solution.3. the calculation of charge density.4. the external Helmoltz plane.

When talking about the acidity of carboxylic acids, is it the same thing to say higher or stronger acidity?

Using the following two half-reactions, determine the pH range in which $NO_2^-\ (aq)$ cannot be found as the predominant chemical species in water.* $NO_3^-(aq)+10H^+(aq)+8e^-\rightarrow NH_4^+(aq)+3H_2O(l),\ pE^{\circ}=14.88$* $NO_2^-(aq)+8H^+(aq)+6e^-\rightarrow NH_4^+(aq)+2H_2O(l),\ pE^{\circ}=15.08$