Chapter 9, Problem 6CT

To determine

To solve the equation using any method

Answer to Problem 6CT

The solution is $x=\frac{1}{4},x=\frac{-7}{4}$ .

Explanation of Solution

Given information:

  ${(4x+3)}^2=16$

Calculation:

The given equation is ${(4x+3)}^2=16$

Solving by rooting both sides,

  $\sqrt{{(4x+3)}^2}=\pm \sqrt{16}$

So,

  $(4x+3)=\pm 4$

For equation to be 0,

  $(4x+3)=4,(4x+3)=-4$

Solving,

  $x=\frac{4-3}{4},x=\frac{-4,-3}{4}$

Hence, the solution is $x=\frac{1}{4},x=\frac{-7}{4}$ .