Owlv2 With Ebook, 1 Term (6 Months) Printed Access Card For Kotz/treichel/townsend/treichel's Chemistry & Chemical Reactivity, 10th
Owlv2 With Ebook, 1 Term (6 Months) Printed Access Card For Kotz/treichel/townsend/treichel's Chemistry & Chemical Reactivity, 10th
10th Edition
ISBN: 9781337791182
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 9, Problem 47GQ

(a)

Interpretation Introduction

Interpretation:

The highest energy occupied molecular orbital (HOMO) and the electron assigned in to it should be determined.

Concept Introduction:

Molecular orbital (MO) theory:  is a method for determining molecular structure in which electrons are not assigned to individual bonds between atoms, but are treated as moving under the influence of the nuclei in the whole molecule.

According to this theory there are two types of orbitals,

  1. (1) Bonding orbitals
  2. (2) Antibonding orbitals

Electrons in molecules are filled in accordance with the energy; the anti-bonding orbital has more energy than the bonding orbitals.

The electronic configuration of oxygen molecule O2 can be represented as follows,

(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2p)2( π2p)4( π*2p)2 

The * represent the antibonding orbital

HOMO and LUMO: This statement stand for highest occupied molecular orbital (HOMO) and lowest unoccupied molecular orbital (LUMO), respectively. So this energy difference between the HOMO and LUMO is termed the HOMO–LUMO gap.

(a)

Expert Solution
Check Mark

Answer to Problem 47GQ

The (σ2p) electron has occupied in HOMO shell. So this electron is assigned for highest orbitals.

Explanation of Solution

Molecular orbital diagram of (CN) molecule can be drawn as

σ*2pz(Antibondingelectrons)π*2pπ*2p2px2py2pz2px2py2pzσ2pzπ2pxπ2py(Bondingelectrons)

         (Antibondingelectrons)(σ*2s)2s2s(Bondingelectrons)(σ2s)2

HOMO-LUMO Analysis: There is one unpaired electron in (σ2p)1 HOMO orbital.

So this molecule have one sigma bond and two pi-bond, the corresponding electronic methods are given above molecular orbital correlation method.

(b)

Interpretation Introduction

Interpretation:

Bond order of the given molecule should be determined.

Concept Introduction:

Molecular orbital (MO) theory:  is a method for determining molecular structure in which electrons are not assigned to individual bonds between atoms, but are treated as moving under the influence of the nuclei in the whole molecule.

According to this theory there are two types of orbitals,

  1. (3) Bonding orbitals
  2. (4) Antibonding orbitals

Electrons in molecules are filled in accordance with the energy; the anti-bonding orbital has more energy than the bonding orbitals.

The electronic configuration of oxygen molecule O2 can be represented as follows,

(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2p)2( π2p)4( π*2p)2 

Bond order: It is the measure of number of electron pairs shared between two atoms.

Bondorder=12(NumberofelectronsinbondoingMOs-NumberofelectronsinantibondingMOs)

The * represent the antibonding orbital

(b)

Expert Solution
Check Mark

Answer to Problem 47GQ

Cyanide (CN) molecule has a bond order of 2.5

Explanation of Solution

Molecular orbital diagram of (CN) molecule can be drawn as

σ*2pz(Antibondingelectrons)π*2pπ*2p2px2py2pz2px2py2pzσ2pzπ2pxπ2py(Bondingelectrons)

         (Antibondingelectrons)(σ*2s)2s2s(Bondingelectrons)(σ2s)2

Calculation method of bond order of CN molecule

The (CN) molecule has seven electrons available in bonding molecular orbitals and two electrons are available in antibonding molecular orbitals so this bond order has shown below. 

  Bondorder=12(NumberofelectronsinbondoingMOs-NumberofelectronsinantibondingMOs)Bondorder=(72)2=52=2.5

(c)

Interpretation Introduction

Interpretation:

Number of net σandπ bonds in the given molecule should be determined.

Concept Introduction:

Molecular orbital (MO) theory:  is a method for determining molecular structure in which electrons are not assigned to individual bonds between atoms, but are treated as moving under the influence of the nuclei in the whole molecule.

According to this theory there are two types of orbitals,

  1. (1) Bonding orbitals
  2. (2) Antibonding orbitals

Electrons in molecules are filled in accordance with the energy; the anti-bonding orbital has more energy than the bonding orbitals.

The electronic configuration of oxygen molecule O2 can be represented as follows,

(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2p)2( π2p)4( π*2p)2 

Bond order: It is the measure of number of electron pairs shared between two atoms.

Bondorder=12(NumberofelectronsinbondoingMOs-NumberofelectronsinantibondingMOs)

The * represent the antibonding orbital

Sigma (σ) bonds are the bonds in which shared hybrid orbital’s electron density are concentrated along the internuclear axis.

Pi (π) bonds are the bonds in which shared unhybridized orbital’s (p, d, etc) electron density are concentrated in above and below of the plane of the molecule.

(c)

Expert Solution
Check Mark

Answer to Problem 47GQ

Cyanide (CN) molecule has a bond order of 2.5 and so net σandπ bond values are 0.5and2 respectively.

Explanation of Solution

Molecular orbital diagram of (CN) molecule can be drawn as

σ*2pz(Antibondingelectrons)π*2pπ*2p2px2py2pz2px2py2pzσ2pzπ2pxπ2py(Bondingelectrons)

         (Antibondingelectrons)(σ*2s)2s2s(Bondingelectrons)(σ2s)2

Calculation method of bond order of CN molecule

The (CN) molecule has seven electrons available in bonding molecular orbitals and two electrons are available in antibonding molecular orbitals so this bond order has shown below. 

  Bondorder=12(NumberofelectronsinbondoingMOs-NumberofelectronsinantibondingMOs)Bondorder=(72)2=52=2.5

This value implies that the net σandπ bond values in CN molecule are 0.5and2 respectively.

(d)

Interpretation Introduction

Interpretation:

It should be checked that whether the CN molecule is paramagnetic or diamagnetic in nature.

Concept Introduction:

Molecular orbital (MO) theory:  is a method for determining molecular structure in which electrons are not assigned to individual bonds between atoms, but are treated as moving under the influence of the nuclei in the whole molecule.

According to this theory there are two types of orbitals,

  1. (1) Bonding orbitals
  2. (2) Antibonding orbitals

Electrons in molecules are filled in accordance with the energy; the anti-bonding orbital has more energy than the bonding orbitals.

The electronic configuration of oxygen molecule O2 can be represented as follows,

(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2p)2( π2p)4( π*2p)2 

Atoms with unpaired electrons are called Paramagnetic. Paramagnetic atoms are attracted to a magnet.

Atoms with paired electrons are called diamagnetic. Diamagnetic atoms are repelled by  a magnet.

(d)

Expert Solution
Check Mark

Explanation of Solution

Molecular orbital diagram of (CN) molecule can be drawn as

σ*2pz(Antibondingelectrons)π*2pπ*2p2px2py2pz2px2py2pzσ2pzπ2pxπ2py(Bondingelectrons)

         (Antibondingelectrons)(σ*2s)2s2s(Bondingelectrons)(σ2s)2

Magnetic property:

The CN molecule has one unpaired electron in (σ2p)1 orbital and so this molecule has paramagnetic nature.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Please correct answer and don't used hand raiting
Differentiate between single links and multicenter links.
I need help on my practice final, if you could explain how to solve this that would be extremely helpful for my final thursday. Please dumb it down chemistry is not my strong suit. If you could offer strategies as well to make my life easier that would be beneficial

Chapter 9 Solutions

Owlv2 With Ebook, 1 Term (6 Months) Printed Access Card For Kotz/treichel/townsend/treichel's Chemistry & Chemical Reactivity, 10th

Ch. 9.3 - The N2+ ions that are formed when electrons with...Ch. 9.3 - What is the empirical formula of Tynan purple?Ch. 9.3 - Butter yellow absorbs light with a wavelength of...Ch. 9.3 - Prob. 2.3ACPCh. 9 - Draw the Lewis structure for chloroform, CHCl3....Ch. 9 - Draw the Lewis structure for NF3. What are its...Ch. 9 - Draw the Lewis structure for hydroxylamine, H2NOH....Ch. 9 - Draw the Lewis structure for 1,...Ch. 9 - Draw the Lewis structure for carbonyl fluoride,...Ch. 9 - Draw the Lewis structure for acetamide, CH3CONH2....Ch. 9 - Specify the electron-pair and molecular geometry...Ch. 9 - Specify the electron-pair and molecular geometry...Ch. 9 - Prob. 9PSCh. 9 - What is the hybrid orbital set used by each of the...Ch. 9 - Draw the Lewis structures of the acid HPO2F2 and...Ch. 9 - Draw the Lewis structures of the arid HSO3F and...Ch. 9 - What is the hybridization of the carbon atom in...Ch. 9 - What is the hybridization of the carbon atoms in...Ch. 9 - What is the electron-pair and molecular geometry...Ch. 9 - What is the electron-pair and molecular geometry...Ch. 9 - Prob. 17PSCh. 9 - For each compound below, decide whether cis and...Ch. 9 - Molecular Orbital Theory (See Examples 9.49.6.)...Ch. 9 - Give the electron configurations for the ions Li2+...Ch. 9 - Calcium carbide, CaC2, contains the acetylide ion,...Ch. 9 - Platinum hexafluoride is an extremely strong...Ch. 9 - When sodium and oxygen react, one of the products...Ch. 9 - When potassium and oxygen react, one of the...Ch. 9 - Among the following, which has the shortest bond...Ch. 9 - Consider the following list of small molecules and...Ch. 9 - Prob. 27PSCh. 9 - The nitrosyl ion. NO+, has an interesting...Ch. 9 - These questions are not designated as to type or...Ch. 9 - What is the OSO angle and the hybrid orbital set...Ch. 9 - Sketch the resonance structures for the nitrite...Ch. 9 - Sketch the resonance structures for the nitrate...Ch. 9 - Sketch the resonance structures for the N2O...Ch. 9 - Compare the structure and bonding in CO2 and CO32...Ch. 9 - Numerous molecules are detected in deep space....Ch. 9 - Acrolein, a component of photochemical smog, has a...Ch. 9 - The organic compound below is a member of a class...Ch. 9 - The compound sketched below is acetylsalicylic...Ch. 9 - Phosphoserine is a less-common amino acid. (a)...Ch. 9 - Lactic acid is a natural compound found in sour...Ch. 9 - Cinnamaldehyde ocaus naturally in cinnamon oil....Ch. 9 - The ion Si2 was reported in a laboratory...Ch. 9 - The simple valence bond picture of O2 does not...Ch. 9 - Nitrogen, N2, can ionize to form N2+ or add an...Ch. 9 - Which of the homonuclear, diatomic molecules of...Ch. 9 - Which of the following molecules or ions are...Ch. 9 - Prob. 47GQCh. 9 - The structure of amphetamine, a stimulant, is...Ch. 9 - Menthol is used in soaps, perfumes, and foods. It...Ch. 9 - Prob. 50GQCh. 9 - Suppose you carry out the following reaction of...Ch. 9 - Ethylene oxide is an intermediate in the...Ch. 9 - The sulfamate ion, H2NSO3, can be thought of as...Ch. 9 - The compound whose structure is shown here is...Ch. 9 - Prob. 55ILCh. 9 - Carbon dioxide (CO2), dinitrogen monoxide (N2O),...Ch. 9 - Draw the two resonance structures that describe...Ch. 9 - Draw a Lewis structure for diimide, HNNH. Then,...Ch. 9 - Prob. 59SCQCh. 9 - Consider the three fluorides BF4, SiF4, and SF4....Ch. 9 - When two amino acids react with each other, they...Ch. 9 - What is the connection between bond order, bond...Ch. 9 - When is it desirable to use MO theory rather than...Ch. 9 - Show how valence bond theory and molecular orbital...Ch. 9 - Three of the four molecular orbitals for...Ch. 9 - Lets look more closely at the process of...Ch. 9 - Borax has the molecular formula Na2B4O5(OH)4. The...Ch. 9 - A model of the organic compound allene is shown...Ch. 9 - Prob. 69SCQCh. 9 - Prob. 70SCQCh. 9 - Bromine forms a number of oxides of varying...Ch. 9 - Prob. 72SCQCh. 9 - Urea reacts with malonic acid to produce...
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
  • Text book image
    Chemistry: Principles and Reactions
    Chemistry
    ISBN:9781305079373
    Author:William L. Masterton, Cecile N. Hurley
    Publisher:Cengage Learning
    Text book image
    Chemistry: Principles and Practice
    Chemistry
    ISBN:9780534420123
    Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
    Publisher:Cengage Learning
    Text book image
    Chemistry
    Chemistry
    ISBN:9781133611097
    Author:Steven S. Zumdahl
    Publisher:Cengage Learning
  • Text book image
    Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Text book image
    Chemistry: An Atoms First Approach
    Chemistry
    ISBN:9781305079243
    Author:Steven S. Zumdahl, Susan A. Zumdahl
    Publisher:Cengage Learning
    Text book image
    Chemistry by OpenStax (2015-05-04)
    Chemistry
    ISBN:9781938168390
    Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
    Publisher:OpenStax
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781133611097
Author:Steven S. Zumdahl
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Text book image
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:OpenStax
INTRODUCTION TO MOLECULAR QUANTUM MECHANICS -Valence bond theory - 1; Author: AGK Chemistry;https://www.youtube.com/watch?v=U8kPBPqDIwM;License: Standard YouTube License, CC-BY