The Physics of Everyday Phenomena
The Physics of Everyday Phenomena
8th Edition
ISBN: 9780073513904
Author: W. Thomas Griffith, Juliet Brosing Professor
Publisher: McGraw-Hill Education
Question
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Chapter 9, Problem 3SP

(a)

To determine

The volume of the block in cubic meters.

(a)

Expert Solution
Check Mark

Answer to Problem 3SP

The volume of the block in cubic meters is 2.7×105 m3.

Explanation of Solution

Given info: The density of the steel block is 7800 kg/m3. The side of the cubic block is 0.03m.

Write the expression to find the volume of the block.

V=a3

Here,

V is the volume of the block

a is the side of the cube

Substitute 0.03m for a in the above equation.

V=(0.03m)3=2.7×105 m3

Conclusion:

Therefore, the volume of the block in cubic meters is 2.7×105 m3.

(b)

To determine

The mass of the block.

(b)

Expert Solution
Check Mark

Answer to Problem 3SP

The mass of the block is 0.21 kg.

Explanation of Solution

Write the expression to find the mass of the block when the density of the block is known.

M=ρV

Here,

ρ is the density of the block

M is the mass of the block

Substitute 7800 kg/m3 for ρ and 2.7×105 m3 for V in the above equation.

M=(7800 kg/m3)(2.7×105 m3)=0.21 kg

Conclusion:

Therefore, the mass of the block is 0.21 kg.

(c)

To determine

The weight of the block.

(c)

Expert Solution
Check Mark

Answer to Problem 3SP

The weight of the block is 2.06N.

Explanation of Solution

Write the equation to find the weight of the block.

W=Mg

Here,

W is the weight of the block

M is the mass of the block

g is the acceleration due to gravity

Substitute 0.21 kg for M and 9.8 m/s2 for g to find the weight of the block.

W=(0.21 kg)(9.8 m/s2)=2.06N

Conclusion:

Therefore, the weight of the block is 2.06N.

(d)

To determine

The buoyant force acting on the block.

(d)

Expert Solution
Check Mark

Answer to Problem 3SP

The buoyant force acting on the block is 0.265 N.

Explanation of Solution

The buoyant force acting on the block is defined as equal to the weight of the water displaced.

Write the equation to find the buoyant force.

Fb=mwg=ρwVwg

Here,

Fb is the buoyant force

ρw is the density of water

Vw is the volume of water displaced

g is the acceleration due to gravity

Substitute 1000 kg/m3 for ρw, 2.7×105 m3 for Vw and 9.8 m/s2 for g in the above equation to find the buoyant force.

Fbouyant=(1000 kg/m3)(2.7×105 m3)(9.8 m/s2)=0.265 N

Conclusion:

Therefore, the buoyant force acting on the block is 0.265 N.

(e)

To determine

The tension in the string needed to hold the block in place.

(e)

Expert Solution
Check Mark

Answer to Problem 3SP

The tension in the string needed to hold the block in place is 1.80 N.

Explanation of Solution

Write the expression of Newton’s first law of motion using the total forces acting on the block to find the tension on the string.

T=WFb

Here,

T is the tension on the string

W is the weight of the block

Fb is the buoyant force

Substitute 2.06N for W and 0.265 N for Fb in the above equation.

T=2.06N0.265 N=1.80 N

Conclusion:

Therefore, the tension in the string needed to hold the block in place is 1.80 N.

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Chapter 9 Solutions

The Physics of Everyday Phenomena

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