Chapter 9, Problem 3ECE

Interpretation Introduction

(a)

Interpretation:

The classification of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ as a strong electrolyte, a weak electrolyte, or a nonelectrolyte is to be stated.

Concept introduction:

The strong electrolytes are those electrolytes having an aqueous solution as a good conductor of electricity. The electrolytes that ionize completely are known as strong electrolytes. The electrolyte which does not ionize completely and has an aqueous solution as a poor conductor is known as a weak electrolyte.

Answer to Problem 3ECE

The compound ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is nonelectrolyte.

Explanation of Solution

The electrolyte is a species that dissolves in solution and conducts electricity. The electrolytes that ionize completely are known as strong electrolytes. The electrolyte which does not ionize completely and has an aqueous solution as a poor conductor is known as a weak electrolyte. Nonelectrolytes are the species whose aqueous solution is the non-conductor of electricity.

The compound ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is a type of sugar and is soluble in water. When ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ dissolved in water it does not conduct electricity. Therefore, the compound ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is nonelectrolyte.

Conclusion

The compound ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is nonelectrolyte.

Interpretation Introduction

(b)

Interpretation:

The major species in the aqueous solution of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is to be identified.

Concept introduction:

The strong electrolytes are those electrolytes having an aqueous solution as a good conductor of electricity. The electrolytes that ionize completely are known as strong electrolytes. The electrolyte which does not ionize completely and has an aqueous solution as a poor conductor is known as a weak electrolyte.

Answer to Problem 3ECE

The major species in the aqueous solution of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}\left(aq\right)$.

Explanation of Solution

The electrolyte is a species that dissolves in solution and conducts electricity. The electrolytes that ionize completely are known as strong electrolytes. The electrolyte which does not ionize completely and has an aqueous solution as a poor conductor is known as a weak electrolyte. Nonelectrolytes are the species whose aqueous solution is the non-conductor of electricity.

The compounds which get completely dissolved in water are called major ionic species. The electrolyte or compounds which partially dissolved in water are called minor ionic species.

The compound ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is a type of sugar and is soluble in water. When ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ dissolved in water it does not conduct electricity. So the compound ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is nonelectrolyte.

The net ionic equation when ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ dissolved in water is shown below.

${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}\left(\text{s}\right)+{\text{H}}_{\text{2}}\text{O}\left(\text{l}\right)\to {\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}\left(aq\right)$

Therefore, the major species in the solution is ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}\left(aq\right)$.

Conclusion

The major species in the aqueous solution of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}\left(aq\right)$.

Interpretation Introduction

(c)

Interpretation:

The minor species in the aqueous solution of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is to be identified.

Concept introduction:

The strong electrolytes are those electrolytes having an aqueous solution as a good conductor of electricity. The electrolytes that ionize completely are known as strong electrolytes. The electrolyte which does not ionize completely and has an aqueous solution as a poor conductor is known as a weak electrolyte.

Answer to Problem 3ECE

There is no minor species in the aqueous solution of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$.

Explanation of Solution

The electrolyte is a species that dissolves in solution and conducts electricity. The electrolytes that ionize completely are known as strong electrolytes. The electrolyte which does not ionize completely and has an aqueous solution as a poor conductor is known as a weak electrolyte. Nonelectrolytes are the species whose aqueous solution is the non-conductor of electricity.

The compounds which get completely dissolved in water are called major ionic species. The electrolyte or compounds which partially dissolved in water are called minor ionic species.

The compound ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is a type of sugar and is soluble in water. When ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ dissolved in water it does not conduct electricity. So the compound ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is nonelectrolyte.

The net ionic equation when ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ dissolved in water is shown below.

${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}\left(\text{s}\right)+{\text{H}}_{\text{2}}\text{O}\left(\text{l}\right)\to {\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}\left(aq\right)$

Therefore, there is no minor species in the aqueous solution of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$.

Conclusion

There is no minor species in the aqueous solution of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$.