COMPUTER SCIENCE:OVERVIEW-TEXT
12th Edition
ISBN: 2810015047178
Author: BROOKSHEAR
Publisher: PEARSON
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Chapter 9, Problem 37CRP
Explanation of Solution
Sequence of operation using “JOIN”, “SELECT”, and “PROJECT”:
LIST1 <- JOIN ASSIGNMENT and JOB
where ASSIGNMENT.JobId = JOB.JobId
LIST2 <- SELECT from LIST1 where ASSIGNMENT.EmpId = '34Y70'
RESULT <- PROJECT JobTitle from LIST2
Explanation for above sequence:
The given SQL statement is used to list the job tile from two relations “Assignment” and “Job” where the value of “EmpId” in relation “Assignment” is “34Y70”
- From the given code, the statement “LIST1 <- JOIN ASSIGNMENT and JOB where ASSIGNMENT.JobId = JOB.JobId” performs join operation.
- It means combine the attributes of both relations “ASSIGNMENT” and “JOB” where the value of “JobId” in relation “ASSIGNMENT” is equal to the value of “JobId” in relation “JOB” and then store it in new relation called “LIST1”...
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Chapter 9 Solutions
COMPUTER SCIENCE:OVERVIEW-TEXT
Ch. 9.1 - Identify two departments in a manufacturing plant...Ch. 9.1 - Prob. 2QECh. 9.1 - Summarize the roles of the application software...Ch. 9.2 - Prob. 1QECh. 9.2 - Prob. 2QECh. 9.2 - Prob. 4QECh. 9.2 - Prob. 5QECh. 9.2 - Prob. 6QECh. 9.3 - Prob. 1QECh. 9.3 - What is a persistent object?
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