Introduction to Information Systems, Binder Ready Version
6th Edition
ISBN: 9781119108009
Author: R. Kelly Rainer, Brad Prince
Publisher: WILEY
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Chapter 9, Problem 2PSA
Program Plan Intro
Amazon’s
- Amazon Mechanical Turk is a marketplace that gets operated to perform a specific work.
- To complete the work human Intelligence it is required.
- The companies can use this web service to access the marketplace to enable a diverse and on-demand work force.
- The human intelligence can be directly utilized by the developers to build their application.
- The main purpose of the Amazon’s Mechanical Turk are:
- Access human intelligence
- Make work scalable
- Performs jobs in a cost effective way
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a. Comment on how you would achieve higher performance for a hypothetical Trent Course
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Implement a C program to find the largest element in a given array. You must have a main function and
a max function.
The function int main() will declare an array with the values {12, 100, 10, 1000, 20, 5}. This
array will be passed to the max function.
The function int max() will perform the necessary operations to find the largest element of
the array.
After max () is finished, have main () print the largest value and its index in the array.
Do not hard code your solution! If we test your code with different array values, we should still
get the correct output.
The following link may help you get started:
https://www.tutorialspoint.com/cprogramming/c_function_call_by_reference.htm
Please run the following program and answer the questions.
#include
int main(void)
{
int arr[6]
=
int *pointer
pointer
*pointer
=
{10, 20, 30, 40, 50, 60};
=
&arr[0];
pointer + 2;
= 5 ;
pointer++;
*pointer
-
(*pointer) 5 ;
pointer++;
*pointer
* (pointer+1)
-
5%;
return 0;
1. [10 pts] Please list the values of elements in array arr after line 8 (*pointer
why.
=
5; ) and explain
Chapter 9 Solutions
Introduction to Information Systems, Binder Ready Version
Ch. 9.1 - Prob. 9.1.1ITACh. 9.1 - Prob. 9.1.2ITACh. 9.1 - Prob. 9.2.1ITACh. 9.1 - Prob. 9.2.2ITACh. 9.1 - Prob. 9.3.1ITACh. 9.1 - Prob. 9.3.2ITACh. 9.2 - Prob. 9.4.1ITACh. 9.2 - Prob. 9.4.2ITACh. 9 - Prob. 1OCCh. 9 - Prob. 2OC
Ch. 9 - Prob. 3OCCh. 9 - Prob. 1DQCh. 9 - Prob. 2DQCh. 9 - Prob. 3DQCh. 9 - Prob. 4DQCh. 9 - Prob. 5DQCh. 9 - Prob. 6DQCh. 9 - Prob. 7DQCh. 9 - Prob. 8DQCh. 9 - Prob. 9DQCh. 9 - Prob. 1PSACh. 9 - Prob. 2PSACh. 9 - Prob. 3PSACh. 9 - Prob. 4PSACh. 9 - Prob. 5PSACh. 9 - Prob. 6PSACh. 9 - Prob. 1CCCh. 9 - Prob. 2CC
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