Chapter 9, Problem 29CR

To determine

Tofind:The $x$ and $y$

Answer to Problem 29CR

  $x=11$

  $y=11\sqrt{2}$

Explanation of Solution

Given information:

Concept Used:

In a ${45}^{\circ }-{45}^{\circ }-{90}^{\circ }$ right angled triangle, length of both legs isequal,and length of hypotenuse is given by product of length of any leg and square root of 2

In a ${30}^{\circ }-{60}^{\circ }-{90}^{\circ }$ right angled triangle, length of longer leg is product of shorter length and square root of 3 and length of hypotenuse is given by twice the length of shorter leg.

Calculation:

We know,

Length of each leg in ${45}^{\circ }-{45}^{\circ }-{90}^{\circ }$ is same

Therefore-

  $x=11$

Length of hypotenuse in ${45}^{\circ }-{45}^{\circ }-{90}^{\circ }$ isproduct of length of any leg and square root of 2

  $y=11\sqrt{2}$