Explanation Given: 6 x 2 + 4 x y + 9 y 2 − 20 = 0 Calculation: Consider the given equation 6 x 2 + 4 x y + 9 y 2 − 20 = 0 . Cot 2 θ = A − B C , cot 2 θ = 6 − 9 4 = − 3 4 ; cos 2 θ = − 3 5 ; sin θ = 1 − ( − 3 5 ) 2 = 2 5 , cos θ = 1 5 ; θ = 63.4 Substituting x , y in the above equation we get, x = 1 5 ( x ′ − 2 y ′ ) , y = 1 5 ( 2 x ′ + y ′ ) 6 ( 1 5 ( x ′ − 2 y ′ ) ) 2 + 4 * 1 5 ( x ′ − 2 y ′ ) * 1 5 ( 2 x ' + y ′ ) + 9 ( 1 5 ( ... To determine To graph: b. x ′ 2 2 − y ′ 2 4 = 1 in x ′ y ′ -plane .

4th Edition

ISBN: 9780135874738

Author: Sullivan

Publisher: PEARSON

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Coordinate Geometry

Coordinate geometry, also known as analytic geometry or Cartesian geometry in classical mathematics, is a type of geometry that is studied using a coordinate system. Coordinate geometry is a branch of mathematics that describes the position of points on …

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Chapter 9, Problem 25RE

To determine

a. The new equation that contains no $x y$ term.

To determine

To graph:

b. $\frac{{x^{'}}^{2}}{2} - \frac{{y^{'}}^{2}}{4} = 1$ in $x^{'} y^{'} -plane$ .

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Chapter 9, Problem 24RE

Chapter 9, Problem 26RE

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a. The new equation that contains no x y term.

Solution Summary: The author calculates that the new equation that contains no x y term is 0 based on the given equation.

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a. The new equation that contains no $x y$ term.

To graph:

b. $\frac{{x^{'}}^{2}}{2} - \frac{{y^{'}}^{2}}{4} = 1$ in $x^{'} y^{'} -plane$ .

Want to see the full answer?

Chapter 9 Solutions

a. The new equation that contains no x y term.

Solution Summary: The author calculates that the new equation that contains no x y term is 0 based on the given equation.

Concept explainers

Videos

a. The new equation that contains no xy term.

To graph: b. x ′ 2 2 − y ′ 2 4 = 1 in x ′ y ′ -plane .

Want to see the full answer?

Chapter 9 Solutions

a. The new equation that contains no $x y$ term.

To graph:

b. $\frac{{x^{'}}^{2}}{2} - \frac{{y^{'}}^{2}}{4} = 1$ in $x^{'} y^{'} -plane$ .