Electrical Wiring Residential
18th Edition
ISBN: 9781285170954
Author: Ray C. Mullin, Phil Simmons
Publisher: Cengage Learning
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Textbook Question
Chapter 9, Problem 25R
May a standard electronic dimmer be used to control the speed of a fan motor? ___________________
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A certain signal f(t) has the following PSD (assume 12 load):
Sp (w) = new + 8(w) - 1.5) + (w + 1.5)]
(a) What is the mean power in the bandwidth w≤2 rad/see?
(b) What is the mean power in the bandwidth -1.9 to 0.99 rad/sec?
Paress(w) dw
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-
(75 Marks)
JA signal (t) is bond
7)(t)(t) and f(t), are band-limited to 1.2 kHz each. These signals are to be
limited to 9.6 kHz, and three other signals
transmitted by means of time-division multiplexing.
Set up scheme for accomplishing this multiplexing requirement, with each signal sampled
at its Nyquist rate.
What must be the speed of the commutator (the output but ram-k bit/sec)?
the minimum band width?
(25 Marks)
Draw the digital modulation outputs, ASK Amplitude Shift Keying) FSK (Frequency Shift
Keying) and PSK (Phase Shift Keying). For baseband and carriet frequency as shown
101
wwwwwwwwwwww
010
BASESAND
basband
CARRIER
Carral
Chapter 9 Solutions
Electrical Wiring Residential
Ch. 9 - What circuit supplies the Master Bedroom?Ch. 9 - What unique type of electrical protection is...Ch. 9 - Prob. 4RCh. 9 - Prob. 5RCh. 9 - Prob. 6RCh. 9 - What is the estimated load in volt-amperes for the...Ch. 9 - Prob. 8RCh. 9 - How many conductors enter the ceiling fan/light...Ch. 9 - What type and size of box may be used for the...Ch. 9 - Prob. 11R
Ch. 9 - a. Does the circuit for the Master Bedroom have a...Ch. 9 - Approximately how many feet (meters) of 2-wire...Ch. 9 - If the cable is laid in notches in the corner...Ch. 9 - Prob. 15RCh. 9 - Prob. 16RCh. 9 - Prob. 17RCh. 9 - Prob. 18RCh. 9 - Prob. 19RCh. 9 - Show your calculations of how to select a proper...Ch. 9 - Prob. 21RCh. 9 - The following is a layout of the lighting circuit...Ch. 9 - Prob. 23RCh. 9 - Prob. 24RCh. 9 - May a standard electronic dimmer be used to...Ch. 9 - Prob. 26R
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- please show full working. I've included the solutionarrow_forwardcan you please show working and steps. The answer is 8kohms.arrow_forwardPSD A certain signal f(t) has the following PSD (assume 12 load): | Sƒ(w) = π[e¯\w\ + 8(w − 2) + +8(w + 2)] (a) What is the mean power in the bandwidth w≤ 1 rad/sec? (b) What is the mean power in the bandwidth 0.99 to 1.01 rad/sec? (c) What is the mean power in the bandwidth 1.99 to 2.01 rad/sec? (d) What is the total mean power in (t)? Pav= + 2T SfLw) dw - SALW)arrow_forward
- An AM modulation waveform signal:- p(t)=(8+4 cos 1000πt + 4 cos 2000πt) cos 10000nt (a) Sketch the amplitude spectrum of p(t). (b) Find total power, sideband power and power efficiency. (c) Find the average power containing of each sideband.arrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forward
- Can you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forwardA. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and Manchester code. Data sequence= (00110100) B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of 50 dB. If the message is a single tone with fm-5 kHz. Determine: 1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio. 2) Minimum required system bandwidth.arrow_forwardFind Io using Mesh analysisarrow_forward
- FM station of 100 MHz carrier frequency modulated by a 20 kHz sinusoid with an amplitude of 10 volt, so that the peak frequency deviation is 25 kHz determine: 1) The BW of the FM signal. 2) The approximated BW if the modulating signal amplitude is increased to 50 volt. 3) The approximated BW if the modulating signal frequency is increased by 70%. 4) The amplitude of the modulating signal if the BW is 65 kHz.arrow_forwardAn FDM is used to multiplex two groups of signals using AM-SSB, the first group contains 25 speech signals, each has maximum frequency of 4 kHz, the second group contains 15 music signals, each has maximum frequency of 10 kHz. A guard bandwidth of 500 Hz is used bety each two signals and before the first one. 1. Find the BWmultiplexing 2. Find the BWtransmission if the multiplexing signal is modulated using AM-DSB-LC.arrow_forwardAn FM signal with 75 kHz deviation, has an input signal-to-noise ratio of 18 dB, with a modulating frequency of 15 kHz. 1) Find SNRO at demodulator o/p. 2) Find SNRO at demodulator o/p if AM is used with m=0.3. 3) Compare the performance in case 1) and 2).. Hint: for single tone AM-DSB-LC, SNR₁ = (2m²) (4)arrow_forward
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