Chapter 9, Problem 24PE

(a)

Interpretation Introduction

Interpretation:

The limiting reactant and the reactant present in excess in the reaction has to be given,

The given reaction is,

  $\text{2Bi}{\left({\text{NO}}_{\text{3}}\right)}_{\text{3}}{\text{+3H}}_{\text{2}}\text{S}\stackrel{}{\to }{\text{Bi}}_{\text{2}}{\text{S}}_{\text{3}}{\text{+6HNO}}_{\text{3}}$

Concept Introduction:

The limiting reactant of the reaction is the reactant that is completely used during the reaction.  Using the mole ratio and starting amounts of the reactants limiting reactant can be determined.

Example:

Consider a reaction starts with $\text{30}{\text{g CaCO}}_{\text{3}}\text{\&}\text{11}\text{g}\text{HCl}\text{.}$ The values in grams has to be converted to moles by dividing with their molecular weights.  According to the mole ratio $\text{0}\text{.3}\text{g}$ of calcium carbonate require $\text{0}\text{.6}\text{g}$ of $\text{HCl}$ completely.  Therefore HCl is the limiting agent.

(b)

Interpretation Introduction

Interpretation:

The limiting reactant and the reactant present in excess in the reaction has to be given,

The given reaction is,

  $\text{3Fe+4}{\text{H}}_{\text{2}}\text{O}\stackrel{}{\to }{\text{Fe}}_{\text{3}}{\text{O}}_{\text{4}}{\text{+4H}}_{\text{2}}$

Concept Introduction:

Refer to part (a).