Explanation Given data: Mass of the jellyfish and water ( m J + m W ) is 3.2 g. Mass of the water ( m W ) that ejected by the jellyfish is 1.3 g, which is written as 1.3 × 10 − 3 kg . The jellyfish takes the water into its bell and then it achieves the speed by ejecting the water. That is, the jellyfish uses the jet propulsion system to gain the speed. Final speed (velocity) of the jellyfish ( v J x ) f is 0.070 m s . Initial speed of the jellyfish ( v J x ) i is 0 m s (since the jellyfish is at the rest). Initial speed of the water ( v W x ) i is 0 m s (since the water is also at the rest in the fish’s bell). It is required to find the final speed of the water ( v W x ) f . Formula used: Write the expression for momentum of conservation for the system of two particles. m 1 v 1 i + m 2 v 2 i = m 1 v 1f + m 2 v 2f (1) Here, m 1 is the mass of the first particle, m 2 is the mass of the second particle, v 1 i is the initial velocity of the first particle, v 2 i is the initial velocity of the second particle, v 1f is the final velocity of the first particle, and v 2f is the final velocity of the second particle. Explanation: From the given data, write the expression for mass of the jellyfish (without water) as follows. m J = ( m J + m W ) − m W (2) Here, m J is the mass of the jellyfish, and m W is the mass of the water. Substitute 3.2 g for ( m J + m W ) , and 1.3 g for m W , m J = 3.2 g − 1.3 g = 1.9 g = 1.9 × 10 − 3 kg Consider the jellyfish and water as two particles. The momentum of the system is conserved for the given data. Modify the expression in equation (1) for the given system as follows. m J ( v J x ) i + m W ( v W x ) i = m J ( v J x ) f + m W ( v W x ) f Rearrange the expression to find the final speed of the jellyfish as follows

4th Edition

ISBN: 8220106755235

Author: Field

Publisher: PEARSON

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Question

Chapter 9, Problem 24P

To determine

To find: The speed of the ejected water.

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Chapter 9, Problem 23P

Chapter 9, Problem 25P

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