Chapter 9, Problem 1SAQ

Interpretation Introduction

Interpretation:

To find out the morality of a solution containing $55.8\text{g}$ of ${\text{MgCl}}_2$ dissolved in $1.00\text{L}$ of solution .

Concept Introduction: Molarity is defined as:

  $\text{Molarity}\text{=}\frac{\text{number}\text{of}\text{moles}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}\text{(L)}}$

Correct answer:

Therefore, option (d) is correct and options (a), (b) and (c), are incorrect.

Explanation of Solution

Reason for the correct statement: Option (d):

  $\begin{array}{l}\text{Molarity}=\frac{\text{weight}\text{of}{\text{MgCl}}_{\text{2}}}{\text{mass}\text{weight}\text{of}{\text{MgCl}}_{\text{2}}}\times \frac{1}{\text{V}\left(\text{lit}\right)}\\ =\frac{55.8\text{g}}{95.211\text{g/mole}}\times \frac{1}{1\text{lit}}\\ =0.586\text{M}\end{array}$