Concept explainers
The correct statement about the energy of emitted electrons when light incident on a metal surface.
Answer to Problem 1MC
Option (b) vary with the
Explanation of Solution
Given Info:
When a photon of sufficient energy incident on a metal surface, its energy is transferred into the electrons on the metal surface. Using this energy, electrons leaves the metal surface and gain kinetic energy. This is called the
Conclusion:
Electrons gain kinetic energy from the energy of photon. Energy of photon strictly depends on its frequency. So energy of emitted electron is proportional to frequency of incident light.is Thus, option (b) is correct.
Intensity of light is a measure of number of photons incident on a unit area. Increase in intensity means the increase in number of incident photons only. Intensity cannot increase the kinetic energy of electron emitted from the metal surface. Thus, option (a) is incorrect.
The kinetic energy of emitted electrons can be calculated using Einstein’s photoelectric equation. Thus, option (d) is incorrect.
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Chapter 9 Solutions
Physical Universe
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- A photon of light has a frequency of 5.00 x 1014 Hz. If the frequency of the photon was doubled then which of these would happen to the energy of this photon? a. it would double b. it would triple c. it would quadruple d. it would become one-fourth as much e. it would become half as mucharrow_forward1. A photon of light has a frequency of 5.00 x 1014 Hz. If the frequency of the photon was doubled then which of these would happen to the energy of this photon? a. it would triple b. it would become one-fourth as much c. it would become half as much d. it would quadruple e. it would doublearrow_forwardA photon of light has a frequency of 5.00 x 1014 Hz. If the frequency of the photon was doubled then which of these would happen to the energy of this photon? a. it would become one-fourth as much b. it would become half as much c. it would double d. it would quadruple e. it would triplearrow_forward
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