The null and alternative hypothesis.

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Answer 1

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 9, Problem 1DHGP

(a)

To determine

The null and alternative hypothesis.

(b)

To determine

The level of significance.

(c)

To determine

To explain: The number of customer’s n is large enough to use the normal distribution to approximate the binomial.

(d)

To determine

To test: The percentage of customers who sample a particular product is more than 60%.

(e)

To determine

Whether the different food products might have a higher or lower percentage of customers trying them.

(f)

To determine

Whetherwecan includeyoungchildreninoursample.

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Microsoft Excel snapshot for random sampling: Also note the formula used for the last column 02 x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51)) A B 1 No. States 2 1 ALABAMA Rand No. 0.925957526 3 2 ALASKA 0.372999976 4 3 ARIZONA 0.941323044 5 4 ARKANSAS 0.071266381 Random Sample CALIFORNIA NORTH CAROLINA ARKANSAS WASHINGTON G7 Microsoft Excel snapshot for systematic sampling: xfx INDEX(SD52:50551, F7) A B E F G 1 No. States Rand No. Random Sample population 50 2 1 ALABAMA 0.5296685 NEW HAMPSHIRE sample 10 3 2 ALASKA 0.4493186 OKLAHOMA k 5 4 3 ARIZONA 0.707914 KANSAS 5 4 ARKANSAS 0.4831379 NORTH DAKOTA 6 5 CALIFORNIA 0.7277162 INDIANA Random Sample Sample Name 7 6 COLORADO 0.5865002 MISSISSIPPI 8 7:ONNECTICU 0.7640596 ILLINOIS 9 8 DELAWARE 0.5783029 MISSOURI 525 10 15 INDIANA MARYLAND COLORADO

Suppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined. 1.What percent of the refunds are more than $3,500? 2. What percent of the refunds are more than $3500 but less than $3579? 3. What percent of the refunds are more than $3325 but less than $3579?

A normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts? 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the answer of the second part.) 2. Compute the probability of a value greater than 55.0. Use the same formula, x=55 and subtract the answer from 1. 3. Compute the probability of a value between 52.0 and 55.0. (The question requires finding probability value between 52 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 52, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…

Answer 2

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 9, Problem 1DHGP

(a)

To determine

The null and alternative hypothesis.

(b)

To determine

The level of significance.

(c)

To determine

To explain: The number of customer’s n is large enough to use the normal distribution to approximate the binomial.

(d)

To determine

To test: The percentage of customers who sample a particular product is more than 60%.

(e)

To determine

Whether the different food products might have a higher or lower percentage of customers trying them.

(f)

To determine

Whetherwecan includeyoungchildreninoursample.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 9, Problem 1DHGP

(a)

To determine

The null and alternative hypothesis.

(b)

To determine

The level of significance.

(c)

To determine

To explain: The number of customer’s n is large enough to use the normal distribution to approximate the binomial.

(d)

To determine

To test: The percentage of customers who sample a particular product is more than 60%.

(e)

To determine

Whether the different food products might have a higher or lower percentage of customers trying them.

(f)

To determine

Whetherwecan includeyoungchildreninoursample.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 9, Problem 1DHGP

(a)

To determine

The null and alternative hypothesis.

(b)

To determine

The level of significance.

(c)

To determine

To explain: The number of customer’s n is large enough to use the normal distribution to approximate the binomial.

(d)

To determine

To test: The percentage of customers who sample a particular product is more than 60%.

(e)

To determine

Whether the different food products might have a higher or lower percentage of customers trying them.

(f)

To determine

Whetherwecan includeyoungchildreninoursample.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 9, Problem 1DHGP

(a)

To determine

The null and alternative hypothesis.

(b)

To determine

The level of significance.

(c)

To determine

To explain: The number of customer’s n is large enough to use the normal distribution to approximate the binomial.

(d)

To determine

To test: The percentage of customers who sample a particular product is more than 60%.

(e)

To determine

Whether the different food products might have a higher or lower percentage of customers trying them.

(f)

To determine

Whetherwecan includeyoungchildreninoursample.

Answer 6

Chapter 9, Problem 1DHGP

(a)

To determine

The null and alternative hypothesis.

Answer 7

Chapter 9, Problem 1DHGP

(a)

To determine

The null and alternative hypothesis.

Answer 8

(b)

To determine

The level of significance.

Answer 9

(b)

To determine

The level of significance.

Answer 10

(c)

To determine

To explain: The number of customer’s n is large enough to use the normal distribution to approximate the binomial.

Answer 11

(c)

To determine

To explain: The number of customer’s n is large enough to use the normal distribution to approximate the binomial.

Answer 12

(d)

To determine

To test: The percentage of customers who sample a particular product is more than 60%.

Answer 13

(d)

To determine

To test: The percentage of customers who sample a particular product is more than 60%.

Answer 14

(e)

To determine

Whether the different food products might have a higher or lower percentage of customers trying them.

Answer 15

(e)

To determine

Whether the different food products might have a higher or lower percentage of customers trying them.

Answer 16

(f)

To determine

Whetherwecan includeyoungchildreninoursample.

Answer 17

(f)

To determine

Whetherwecan includeyoungchildreninoursample.

Answer 18

Expert Solution & Answer

Answer 19

Expert Solution & Answer

Answer 20

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Answer 21

The null and alternative hypothesis.

Solution Summary: The author explains the null hypothesis and the alternative hypothesis. The sample size is large enough to use the normal distribution to approximate the binomial.

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The null and alternative hypothesis.

The level of significance.

To explain: The number of customer’s n is large enough to use the normal distribution to approximate the binomial.

To test: The percentage of customers who sample a particular product is more than 60%.

Whether the different food products might have a higher or lower percentage of customers trying them.

Whetherwecan includeyoungchildreninoursample.

Want to see the full answer?

Chapter 9 Solutions