COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781711470832
Author: OpenStax
Publisher: XANEDU
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Chapter 9, Problem 10TP
To determine

The applied force Fi and an explanation behind the total weight w with the range of values over which the force could exist.

Expert Solution & Answer
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Answer to Problem 10TP

The applied force is around 58N and the forces that should be applied to the wheel barrow should be in range of 14N to 58N.

Explanation of Solution

Given:

Number of bricks in the wheel barrow is 20.

Mass of each brick is 3kg.

Formula used:

Write the expression for force.

  F=mg

Here, F is the force, m is the mass and g is the acceleration due to gravity.

Write the expression for torque.

  τnet=Fnetl0

The mechanical MA advantage of the lever is given as,

  MA=lil0

The torque due to the output force is equal n magnitude and opposite in direction o the torque caused by the weight. Thus,

  (F out)(l0)=(F net)(l0)Fout=Fnet

Since, the mechanical advantage is the ratio of output force to input force. The ratio can be written as,

  FoutFin=lil0

Conclusion:

Force due to wheelbarrow is calculated as,

  Fwheelbarrow=mg=(20kg)(9.8m/ s 2)=196N

Force due to the weight of 20 bricks is calculated as,

  Fbricks=20(mg)=20(3kg)(9.8m/ s 2)=588N

Total force due to the weight is calculated as,

  Fnet=Fwheelbarrow+Fbricks=(196N)+(588N)=784N

The net torque s calculated as,

  τnet=Fnetl0=(784N)l0

The output force is calculated as,

  Fout=Fnet=(784N)=784N

The input force is calculated as,

  F outF in=lil0784NF in=1.02m0.075mFin=57.65NFin58N

For an empty wheelbarrow the output force is, Fout=196N

The input force for an empty wheelbarrow is calculated as,

  F outF in=lil0196NF in=1.02m0.075mFin=14.41NFin14N

Conclusion:

Therefore, the applied force is around 58N and the forces that should be applied to the wheel barrow should be in range of 14N to 58N.

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Chapter 9 Solutions

COLLEGE PHYSICS

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