Explanation Given: The given equation of the circle is, x 2 + 16 x + y 2 + 39 = 0 Definition: The standard equation of the circle is, ( x − h ) 2 + ( y − k ) 2 = r 2 Here, ( h , k ) is the center of the circle and r is radius. Calculation: Consider the given equation, x 2 + 16 x + y 2 + 39 = 0 Express the given equation into the standard form by completing the square. x 2 + 16 x + y 2 + 39 = 0 ( x 2 + 16 x + 8 2 ) + ( y 2 − 0 y + 0 2 ) = − 39 + 8 2 + 0 2 ( x 2 + 16 x + 64 ) +

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ISBN: 9781285195728

Author: Jerome E. Kaufmann, Karen L. Schwitters

Publisher: Cengage Learning

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Chapter 8.CR, Problem 14CR

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The center and the length of radius for the given equation of circle is x2+16x+y2+39=0

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The center and the length of radius for the given equation of circle is x 2 + 16 x + y 2 + 39 = 0

Solution Summary: The author explains that the given equation of the circle is, x2+16x+y 2 +39=0. The value of (x-h)

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The center and the length of radius for the given equation of circle is x2+16x+y2+39=0

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Chapter 8 Solutions

The center and the length of radius for the given equation of circle is x 2 + 16 x + y 2 + 39 = 0

Solution Summary: The author explains that the given equation of the circle is, x2+16x+y 2 +39=0. The value of (x-h)

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To find: The center and the length of radius for the given equation of circle is x2+16x+y2+39=0

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Chapter 8 Solutions

To find:

The center and the length of radius for the given equation of circle is x2+16x+y2+39=0