Explanation Given: The given equation of circle is, x 2 + y 2 + 4 x + 4 y − 8 = 0 Approach: The standard form of the equation of circle is given by, ( x − h ) 2 + ( y − k ) 2 = r 2 Where, r is the radius of the circle and ( h , k ) is the coordinates of the center of the circle. Calculation: The given equation of circle is, x 2 + y 2 + 4 x + 4 y − 8 = 0 …… ( 1 ) Transform equation ( 1 ) to the standard form. x 2 + y 2 + 4 x + 4 y = 8 ( x 2 + 2 ( x ) ( 2 ) + 2 2 ) + ( y 2 + 2 ( y )</

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ISBN: 9781285195728

Author: Jerome E. Kaufmann, Karen L. Schwitters

Publisher: Cengage Learning

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Chapter 8.2, Problem 43PS

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The graph of circle x2+y2+4x+4y−8=0.

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Chapter 8.2, Problem 42PS

Chapter 8.2, Problem 44PS

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Chapter 8 Solutions

Intermediate Algebra

Ch. 8.1 - For Problems 110, answer true or false. The graph...Ch. 8.1 - Prob. 2CQ Ch. 8.1 - Prob. 3CQ Ch. 8.1 - Prob. 4CQ Ch. 8.1 - Prob. 5CQ Ch. 8.1 - Prob. 6CQ Ch. 8.1 - Prob. 7CQ Ch. 8.1 - Prob. 8CQ Ch. 8.1 - Prob. 9CQ Ch. 8.1 - Prob. 10CQ

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To plot: The graph of circle x 2 + y 2 + 4 x + 4 y − 8 = 0 .

Solution Summary: The author illustrates the graph of circle x2+y2, +4x+4y-8=0.

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To plot:

The graph of circle x2+y2+4x+4y−8=0.

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Chapter 8 Solutions

To plot: The graph of circle x 2 + y 2 + 4 x + 4 y − 8 = 0 .

Solution Summary: The author illustrates the graph of circle x2+y2, +4x+4y-8=0.

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To plot: The graph of circle x2+y2+4x+4y−8=0.

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Chapter 8 Solutions

To plot:

The graph of circle x2+y2+4x+4y−8=0.