BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD)
8th Edition
ISBN: 9781337687539
Author: Brown/Iverson/Anslyn/ Foote
Publisher: CENGAGE C
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Textbook Question
Chapter 8.7, Problem DQ
The strength of the H─O bond in vitamin E is weaker than the C─H from which the hydrogen is abstracted in the fatty acid primarily because,
- 1. O─H bonds are always weaker than C─H bonds.
- 2. The radical created from hydrogen abstraction from O─H is stabilized by resonance delocalization and many of the contributing structures have secondary carbon radical character.
- 3. The sp2 hybridization of the phenyl ring changes the hybridization of the oxygen in the O─H bond.
- 4. The radical created from hydrogen abstraction from O─H is stabilized by resonance delocalization and many of the contributing structures have tertiary carbon radical character.
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Study this 'H NMR spectrum, and then answer the questions about it in the table below.
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1.0-
0.5-
0.0
10.0
9.0
8.0
7.0
6.0
5.0
4.0
3.0
2.0
1.0
0.0
What unit symbol should be written on the horizontal axis?
What is the chemical shift & of the doublet?
If there is no doublet, just check the box instead.
Give your answer to 2 significant digits.
What is the chemical shift of the signal immediately upfield of the doublet?
If there is no doublet, or no signal upfield of it, check the box instead.
What is the chemical shift & of the least deshielded proton?
If you can't tell without more information, check the box instead.
血
8 = ☐
There is no doublet.
8 = ☐
No such signal.
8 = 0
Need more information.
how many moles of H2O2 are required to react with 11g of N2H4 according to the following reaction? (atomic weights: N=14.01, H=1.008, O= 16.00) 7H2O2 + N2H4 -> 2HNO3 + 8H20
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Chapter 8 Solutions
BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD)
Ch. 8.2 - Prob. 8.1PCh. 8.4 - Name and draw structural formulas for all...Ch. 8.4 - Using the table of bond dissociation enthalpies in...Ch. 8.5 - Prob. 8.4PCh. 8.6 - Given the solution to Example 8.5, predict the...Ch. 8.7 - Prob. 8.6PCh. 8.7 - Linoleic acid is shown below. What makes this...Ch. 8.7 - Prob. BQCh. 8.7 - Prob. CQCh. 8.7 - The strength of the HO bond in vitamin E is weaker...
Ch. 8.7 - Prob. EQCh. 8.8 - Prob. 8.7PCh. 8 - Prob. 8.8PCh. 8 - Prob. 8.9PCh. 8 - Prob. 8.10PCh. 8 - Prob. 8.11PCh. 8 - Account for the fact that among the chlorinated...Ch. 8 - Name and draw structural formulas for all possible...Ch. 8 - Prob. 8.14PCh. 8 - There are three constitutional isomers with the...Ch. 8 - Following is a balanced equation for bromination...Ch. 8 - Prob. 8.17PCh. 8 - Prob. 8.18PCh. 8 - Prob. 8.19PCh. 8 - Cyclobutane reacts with bromine to give...Ch. 8 - Prob. 8.21PCh. 8 - Following is a balanced equation for the allylic...Ch. 8 - Prob. 8.23PCh. 8 - Prob. 8.24PCh. 8 - The major product formed when methylenecyclohexane...Ch. 8 - Prob. 8.26PCh. 8 - Prob. 8.27PCh. 8 - Prob. 8.28PCh. 8 - Write the products of the following sequences of...Ch. 8 - Using your reaction roadmap as a guide, show...Ch. 8 - Prob. 8.31PCh. 8 - Prob. 8.32PCh. 8 - Prob. 8.33PCh. 8 - Prob. 8.34P
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