Chapter 8.7, Problem 50P

Mental Math For Exercises 49-51, find a pair of factors for each number by using the difference of two squares.

28

To determine

To find a pair of factors of the number $28$ using the difference of two squares.

Answer to Problem 50P

A pair of factors of the given number are $\left(2\right)\left(14\right)$ .

Explanation of Solution

Given information:

Given number $28$

Given$28=64-36$

  $=8^2-6^2$

As we know that $a^2-b^2=\left(a+b\right)\left(a-b\right)$

Put $a=8,b=6$ , we get $8^2-6^2=\left(8-6\right)\left(8+6\right)$

  $=\left(2\right)\left(14\right)$

Hence, a pair of factors of the given number are $\left(2\right)\left(14\right)$ .