The product obtained for given hydroboration-oxidation has to be drawn. Concept Introduction: Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition. Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

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Answer 1

Question

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

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NMR spectrum of ethyl acetate has signals whose chemical shifts are indicated below. Which hydrogen or set of hydrogens corresponds to the signal at 4.1 ppm? Select the single best answer. The H O HỌC—C—0—CH, CH, 2 A ethyl acetate H NMR: 1.3 ppm, 2.0 ppm, 4.1 ppm Check OA B OC ch B C Save For Later Submit Ass © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center |

How many signals do you expect in the H NMR spectrum for this molecule? Br Br Write the answer below. Also, in each of the drawing areas below is a copy of the molecule, with Hs shown. In each copy, one of the H atoms is colored red. Highlight in red all other H atoms that would contribute to the same signal as the H already highlighted red Note for advanced students: In this question, any multiplet is counted as one signal. 1 Number of signals in the 'H NMR spectrum. For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. Check For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. O ✓ No additional Hs to color in top molecule ง No additional Hs to color in bottom…

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Answer 2

Question

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

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Answer 3

Question

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

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Answer 4

Question

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

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Answer 5

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 6

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 7

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 10

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 8.4 - Prob. 1CC Ch. 8.4 - Prob. 2CC Ch. 8.4 - Draw a mechanism for the following...Ch. 8.4 - Prob. 3PTS Ch. 8.4 - Prob. 4ATS Ch. 8.4 - Prob. 5CC Ch. 8.4 - Prob. 2LTS Ch. 8.4 - Prob. 6PTS Ch. 8.5 - Prob. 8CC Ch. 8.5 - Prob. 9CC

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