To determine The percentages of the rate of exergy input with fuel entering the combustor unit, all the outputs, losses, and destructions of exergy for the cogeneration cycle. Explanation Write the expression for exergy increase in the steam generator. ( Φ ˙ 1 − Φ ˙ 5 ) S G = m ˙ 1 [ ( h 1 − h 5 ) − T o ( s 1 − s 5 ) ] (I) Here, mass flow rate of steam passing through the steam generator, specific entropy of steam at inlet of steam generator is s 5 , specific entropy of steam at exit of steam generator is s 1 , specific enthalpy of steam at inlet of steam generator is h 5 and the specific enthalpy of steam at exit of steam generator is h 1 . Write the expression for exergy loss in high pressure turbine. ( Φ ˙ 1 − Φ ˙ 2 ) H T = m ˙ 1 [ ( h 1 − h 2 ) − T o ( s 1 − s 2 ) ] (II) Here, the specific entropy of steam at exit of high pressure turbine is s 2 and the specific enthalpy of steam at exit of high pressure turbine is h 2 . Write the expression for exergy loss in low pressure turbine. ( Φ ˙ 2 − Φ ˙ 3 ) L T = m ˙ 1 [ ( h 2 − h 3 ) − T o ( s 2 − s 3 ) ] (III) Here, entropy of steam at exit of low pressure turbine is s 3 and enthalpy of steam at exit of low pressure turbine is h 3 . Write the expression for exergy loss in building heater. ( Φ ˙ 2 − Φ ˙ 6 ) B H = m ˙ 1 [ ( h 2 − h 6 ) − T o ( s 2 − s 6 ) ] (IV) Here, specific entropy of steam at exit of building heater is s 6 and specific enthalpy of steam at exit of building heater is h 6 . Write the expression for exergy loss in trap. ( Φ ˙ 6 − Φ ˙ 7 ) T = m ˙ 1 [ ( h 6 − h 7 ) − T o ( s 6 − s 7 ) ] (V) Here, specific entropy of steam at exit of trap is s 7 and specific enthalpy of steam at exit of trap is h 7 . Write the expression for exergy decrease in condenser. ( Φ ˙ 3 − 4 − Φ ˙ 7 − 8 ) C = m ˙ 3 [ ( h 3 − h 4 ) − T o ( s 3 − s 4 ) ] + m ˙ 2 [ ( h 7 − h 4 ) − T o ( s 7 − s 4 ) ] (VI) Here, specific entropy of steam at exit of condenser is s 4 and specific enthalpy of steam at exit of condenser is h 4 . Write the expression for exergy increase in pump. ( Φ ˙ 4 − Φ ˙ 5 ) P = m ˙ 1 [ ( h 4 − h 5 ) − T o ( s 4 − s 5 ) ] (VII) Here, specific entropy of steam at exit of pump is s 5 and specific enthalpy of steam at exit of pump is h 5 . Write the expression for percentage of exergy lost in stack with respect to exergy loss in fuel. Φ s t a c k i n % = ( Φ s t a c k Φ F u e l × 100 ) % (VIII) Here, exergy of fuel combustion is Φ F u e l and exergy loss in stack is Φ s t a c k . Write the expression for percentage of exergy increase in steam generator with respect to exergy loss in fuel. ( Φ ˙ 1 − Φ ˙ 5 ) S G i n % = ( ( Φ ˙ 1 − Φ ˙ 5 ) S G Φ F u e l × 100 ) % (IX) Here, exergy of fuel combustion is Φ F u e l and exergy increase in steam generator is ( Φ ˙ 1 − Φ ˙ 5 ) S G . Write the expression for percentage of exergy decrease in high pressure turbine with respect to exergy loss in fuel. ( Φ ˙ 1 − Φ ˙ 2 ) H T i n % = ( ( Φ ˙ 1 − Φ ˙ 2 ) H T Φ F u e l × 100 ) % (X) Here, exergy of fuel combustion is Φ F u e l and exergy decrease in high pressure turbine is ( Φ ˙ 1 − Φ ˙ 2 ) H T . Write the expression for percentage of exergy decrease in low pressure turbine with respect to exergy loss in fuel. ( Φ ˙ 2 − Φ ˙ 3 ) L T i n % = ( ( Φ ˙ 2 − Φ ˙ 3 ) L T Φ F u e l × 100 ) % (XI) Here, exergy of fuel combustion is Φ F u e l and exergy decrease in low pressure turbine is ( Φ ˙ 2 − Φ ˙ 3 ) L T . Write the expression for percentage of exergy decrease in building heater with respect to exergy loss in fuel. ( Φ ˙ 2 − Φ ˙ 6 ) B H i n % = ( ( Φ ˙ 2 − Φ ˙ 6 ) B H Φ F u e l × 100 ) % (XII) Here, exergy of fuel combustion is Φ F u e l and exergy decrease in building heater is ( Φ ˙ 2 − Φ ˙ 6 ) B H . Write the expression for percentage of exergy decrease in trap with respect to exergy loss in fuel. ( Φ ˙ 6 − Φ ˙ 7 ) T i n % = ( ( Φ ˙ 6 − Φ ˙ 7 ) T Φ F u e l × 100 ) % (XIII) Here, exergy of fuel combustion is Φ F u e l and exergy decrease in trap is ( Φ ˙ 6 − Φ ˙ 7 ) T . Write the expression for percentage of exergy increase in pump with respect to exergy loss in fuel. ( Φ ˙ 4 − Φ ˙ 5 ) P i n % = ( ( Φ ˙ 4 − Φ ˙ 5 ) P Φ F u e l × 100 ) % (XIV) Here, exergy of fuel combustion is Φ F u e l and exergy increase in pump is ( Φ ˙ 4 − Φ ˙ 5 ) P . Write the expression for percentage of exergy decrease in condenser with respect to exergy loss in fuel. ( Φ ˙ 3 − 4 − Φ ˙ 7 − 8 ) C i n % = ( ( Φ ˙ 3 − 4 − Φ ˙ 7 − 8 ) C Φ ˙ F u e l × 100 ) % (XV) Here, exergy of fuel combustion is Φ F u e l and exergy decrease in condenser is ( Φ ˙ 3 − 4 − Φ ˙ 7 − 8 ) C . Conclusion: Substitute 1 kg/s for m ˙ 1 , 2992.7 kJ/kg for h 1 , 193.34 kJ/kg for h 5 , 0.6539 kJ/kg ⋅ K for s 5 , 298 ° K for T o and 6.8381 kJ/kg ⋅ K for s 1 in Equation (I). ( Φ ˙ 1 − Φ ˙ 5 ) S G = ( 1 kg/s ) [ ( 2992.7 kJ/kg − 193.34 kJ/kg ) − ( 298 K ) ( 6.8381 kJ/kg ⋅ K − 0.6539 kJ/kg ⋅ K ) ] = ( 1 kg/s ) [ ( 2799.36 kJ/kg ) − ( 298 K ) ( 6.1842 kJ/kg ⋅ K ) ] = ( 1 kg/s ) [ ( 2799.36 kJ/kg ) − ( 1842.89 kJ/kg ) ] = 956.468 kW Thus, the exergy increase in the steam generator is 956.468 kW . Substitute 1 kg/s for m ˙ 1 , 2992.7 kJ/kg for h 1 , 2652.9 kJ/kg for h 2 , 6.9906 kJ/kg ⋅ K for s 2 , 298 ° K for T o and 6.8381 kJ/kg ⋅ K for s 1 in Equation (II). ( Φ ˙ 1 − Φ ˙ 2 ) H T = ( 1 kg/s ) [ ( 2992.7 kJ/kg − 2652.9 kJ/kg ) − ( 298 K ) ( 6.8381 kJ/kg ⋅ K − 6.9906 kJ/kg ⋅ K ) ] = ( 1 kg/s ) [ ( 339.8 kJ/kg ) + ( 298 K ) ( 0.1525 kJ/kg ⋅ K ) ] = ( 1 kg/s ) [ ( 339.8 kJ/kg ) + ( 45.44 kJ/kg ) ] = 387.3608 kW Thus, the exergy loss in high pressure turbine is 387.3608 kW . Substitute 1 kg/s for m ˙ 1 , 2280.4 kJ/kg for h 3 , 2652.9 kJ/kg for h 2 , 6.9906 kJ/kg ⋅ K for s 2 , 298 ° K for T o and 7.1965 kJ/kg ⋅ K for s 3 in Equation (III). ( Φ ˙ 2 − Φ ˙ 3 ) L T = ( 1 kg/s ) [ ( 2652.9 kJ/kg − 2280.4 kJ/kg ) − ( 298 K ) ( 6.9906 kJ/kg ⋅ K − 7.1965 kJ/kg ⋅ K ) ] = ( 1 kg/s ) [ ( 372

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118832301

Author: SHAPIRO

Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT

See similar textbooks

Videos

Question

Chapter 8.6, Problem 92P

To determine

The percentages of the rate of exergy input with fuel entering the combustor unit, all the outputs, losses, and destructions of exergy for the cogeneration cycle.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 8.6, Problem 91P

Chapter 8.6, Problem 93P

Students have asked these similar questions

The resistance R and load effect S for a given failure mode are statistically independent random variables with marginal PDF's 1 fR (r) = 0≤r≤100 100' fs(s)=0.05e-0.05s (a) Determine the probability of failure by computing the probability content of the failure domain defined as {r

Please solve this problem as soon as possible My ID# 016948724

The gears shown in the figure have a diametral pitch of 2 teeth per inch and a 20° pressure angle. The pinion rotates at 1800 rev/min clockwise and transmits 200 hp through the idler pair to gear 5 on shaft c. What forces do gears 3 and 4 transmit to the idler shaft? TS I y 18T 32T This a 12 x 18T C 48T 5

Chapter 8 Solutions

Fundamentals of Engineering Thermodynamics

Ch. 8.6 - Prob. 1E Ch. 8.6 - Prob. 2E Ch. 8.6 - Prob. 3E Ch. 8.6 - Prob. 4E Ch. 8.6 - Prob. 5E Ch. 8.6 - Prob. 6E Ch. 8.6 - Prob. 7E Ch. 8.6 - 8. What is the relationship between global climate...Ch. 8.6 - Prob. 9E Ch. 8.6 - Prob. 10E

Ch. 8.6 - Prob. 11E Ch. 8.6 - Prob. 12E Ch. 8.6 - Prob. 13E Ch. 8.6 - Prob. 1CU Ch. 8.6 - Prob. 2CU Ch. 8.6 - 3. The component of the Rankine cycle in which the...Ch. 8.6 - 4. A cycle that couples two vapor cycles so the...Ch. 8.6 - 5. The ratio of the pump work input to the work...Ch. 8.6 - 6. A shell-and-tube-type recuperator in which the...Ch. 8.6 - Prob. 7CU Ch. 8.6 - Prob. 8CU Ch. 8.6 - Prob. 9CU Ch. 8.6 - Prob. 10CU Ch. 8.6 - 11. An example of an external irreversibility...Ch. 8.6 - Prob. 12CU Ch. 8.6 - Prob. 13CU Ch. 8.6 - Prob. 14CU Ch. 8.6 - 15. A direct-contact–type heat exchanger found in...Ch. 8.6 - 16. The component of a regenerative vapor power...Ch. 8.6 - Prob. 17CU Ch. 8.6 - 18. A Rankine cycle that employs an organic...Ch. 8.6 - Prob. 19CU Ch. 8.6 - Prob. 20CU Ch. 8.6 - Prob. 21CU Ch. 8.6 - Prob. 22CU Ch. 8.6 - Prob. 23CU Ch. 8.6 - 24. The purpose of deaeration is ______________. Ch. 8.6 - Prob. 25CU Ch. 8.6 - Prob. 26CU Ch. 8.6 - Prob. 27CU Ch. 8.6 - Prob. 28CU Ch. 8.6 - 29. The total cost associated with a power plant...Ch. 8.6 - Prob. 30CU Ch. 8.6 - Prob. 31CU Ch. 8.6 - Prob. 32CU Ch. 8.6 - Prob. 33CU Ch. 8.6 - Prob. 34CU Ch. 8.6 - Prob. 35CU Ch. 8.6 - Prob. 36CU Ch. 8.6 - Prob. 37CU Ch. 8.6 - Prob. 38CU Ch. 8.6 - Prob. 39CU Ch. 8.6 - 40. For a vapor power cycle with and , the...Ch. 8.6 - Prob. 41CU Ch. 8.6 - Prob. 42CU Ch. 8.6 - Prob. 43CU Ch. 8.6 - Prob. 44CU Ch. 8.6 - Prob. 45CU Ch. 8.6 - Prob. 46CU Ch. 8.6 - Prob. 47CU Ch. 8.6 - Prob. 48CU Ch. 8.6 - Prob. 49CU Ch. 8.6 - 50. In a binary cycle, energy discharged by heat...Ch. 8.6 - Prob. 1P Ch. 8.6 - Prob. 2P Ch. 8.6 - Prob. 3P Ch. 8.6 - Prob. 6P Ch. 8.6 - 8.7 Water is the working fluid in an ideal Rankine...Ch. 8.6 - Prob. 8P Ch. 8.6 - 8.10 Water is the working fluid in an ideal...Ch. 8.6 - Prob. 12P Ch. 8.6 - Prob. 13P Ch. 8.6 - 8.14 On the south coast of the island of Hawaii,...Ch. 8.6 - Prob. 15P Ch. 8.6 - 8.17. Water is the working fluid in a Rankine...Ch. 8.6 - 8.19 Water is the working fluid in a Rankine...Ch. 8.6 - Prob. 20P Ch. 8.6 - Prob. 21P Ch. 8.6 - 8.22 Superheated steam at 8 MPa and 480°C leaves...Ch. 8.6 - Prob. 23P Ch. 8.6 - Prob. 25P Ch. 8.6 - Prob. 26P Ch. 8.6 - 8.27 Steam is the working fluid in the ideal...Ch. 8.6 - Prob. 28P Ch. 8.6 - Prob. 29P Ch. 8.6 - Prob. 30P Ch. 8.6 - Prob. 31P Ch. 8.6 - 8.32 An ideal Rankine cycle with reheat uses water...Ch. 8.6 - Prob. 33P Ch. 8.6 - 8.34 Steam at 4800 lbf/in.2, 1000℉ enters the...Ch. 8.6 - Prob. 35P Ch. 8.6 - Prob. 37P Ch. 8.6 - 8.38 For the cycle of Problem 8.37, reconsider the...Ch. 8.6 - Prob. 39P Ch. 8.6 - Prob. 40P Ch. 8.6 - Prob. 41P Ch. 8.6 - Prob. 42P Ch. 8.6 - Prob. 43P Ch. 8.6 - Prob. 44P Ch. 8.6 - Prob. 45P Ch. 8.6 - Prob. 46P Ch. 8.6 - Prob. 47P Ch. 8.6 - 8.48 For the cycle of Problem 8.47, investigate...Ch. 8.6 - Prob. 49P Ch. 8.6 - Prob. 50P Ch. 8.6 - Prob. 51P Ch. 8.6 - 8.52 As indicated in Fig. P8.52, a power plant...Ch. 8.6 - Prob. 53P Ch. 8.6 - Prob. 54P Ch. 8.6 - Prob. 55P Ch. 8.6 - Prob. 56P Ch. 8.6 - Prob. 57P Ch. 8.6 - Prob. 58P Ch. 8.6 - Prob. 59P Ch. 8.6 - Prob. 60P Ch. 8.6 - Prob. 61P Ch. 8.6 - Prob. 63P Ch. 8.6 - Prob. 64P Ch. 8.6 - Prob. 65P Ch. 8.6 - Prob. 66P Ch. 8.6 - 8.67 Water is the working fluid in a Rankine cycle...Ch. 8.6 - Prob. 68P Ch. 8.6 - Prob. 69P Ch. 8.6 - Prob. 70P Ch. 8.6 - 8.72 Water is the working fluid in a...Ch. 8.6 - Prob. 73P Ch. 8.6 - Prob. 74P Ch. 8.6 - Prob. 75P Ch. 8.6 - 8.76 A binary vapor power cycle consists of two...Ch. 8.6 - A binary vapor cycle consists of two Rankine...Ch. 8.6 - Prob. 78P Ch. 8.6 - Prob. 79P Ch. 8.6 - Prob. 80P Ch. 8.6 - 8.81 Figure P8.81 shows a combined heat and power...Ch. 8.6 - 8.82 Figure P8.82 shows a cogeneration cycle that...Ch. 8.6 - Prob. 83P Ch. 8.6 - 8.84 The steam generator of a vapor power plant...Ch. 8.6 - 8.85 Determine the exergy input, in kJ per kg of...Ch. 8.6 - 8.86 In the steam generator of the cycle of...Ch. 8.6 - Prob. 87P Ch. 8.6 - 8.88 Determine the rate of exergy input, in Btu/h,...Ch. 8.6 - Prob. 89P Ch. 8.6 - Prob. 90P Ch. 8.6 - Prob. 91P Ch. 8.6 - 8.92 Figure P8.92 provides steady-state operating...Ch. 8.6 - 8.93 Steam enters the turbine of a simple vapor...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.