(a) To determine The net power developed. Explanation The T-s diagram with all given states is shown below. Figure-(1) Write the expression for the specific entropy at point 2 s . s 2 s = s f + x 2 s s f g (I) Here, the specific entropy of the saturated water is s f and the specific entropy of the water-vapor mixture is s f g and the dryness fraction is x 2 s . Write the expression for the specific enthalpy at point 2 s . h 2 s = h f + x 2 s h f g (II) Here, the specific enthalpy of the saturated water is h f and the specific enthalpy of the water-vapor mixture is h f g and the dryness fraction is x 2 s . Write the expression for the specific enthalpy at point 2. h 2 = h 1 − η T ( h 1 − h 2 s ) (III) Here, the enthalpy at point 1 is h 1 , and the isentropic efficiency of the turbine is η T . Write the expression for the specific entropy at point 3. s 3 s = s f + x 3 s s f g (IV) Here, the specific entropy of the saturated water is s f and the specific entropy of the water vapor mixture is s f g and the dryness fraction is x 3 s . Write the expression for the specific enthalpy at point 3s. h 3 s = h f + x 3 s h f g (V) Here, the specific enthalpy of the saturated water is h f and the specific enthalpy of the water vapor mixture is h f g and the dryness fraction is x 3 s corresponding to point 3 s . Write the expression for the specific enthalpy at point 3. h 3 = h 2 − η T ( h 2 − h 3 s ) (VI) Here, the enthalpy at point 3 is h 3 and at 3s is h 3 s and the isentropic efficiency of the turbine is η T . Write the expression for the enthalpy at point 5. h 5 = h 4 + v 4 ( p 5 − p 4 ) η p (VII) Here, the pressure at the point 5 is p 5 , the pressure at the point 4 is p 4 , the specific volume at point 4 is v 4 , the specific enthalpy at state 5 is h 5 , the specific enthalpy at state 4 is h 4 and the isentropic efficiency of the pump is η P . Write the expression for the enthalpy at point 7. h 7 = h 6 + v 6 ( p 7 − p 6 ) η P (VIII) Here, the pressure at the point 7 is p 7 , the pressure at the point 6 is p 6 , the specific volume at point 6 is v 6 , the specific enthalpy at state 7 is h 7 and the specific enthalpy at state 6 is h 6 . Write the expression for the fraction of the mass of steam entering in to feed water heater before entering into second stage turbine. y = ( h 6 − h 5 ) ( h 2 − h 5 ) (IX) Write the expression for the turbine work. W T m ˙ = ( h 1 − h 2 ) + ( 1 − y ) ( h 2 − h 3 ) (X) Here, the mass flow rate of the steam is m ˙ . Write the expression for the pump work. W P m ˙ = ( h 7 − h 6 ) + ( 1 − y ) ( h 5 − h 4 ) (XI) Write the expression for the net work. W n e t = W T − W P (XII) Conclusion: Refer to Table A-4, “Properties of Superheated water vapour” to obtain specific enthalpy as 3465.4 kJ / kg and the specific entropy 6.5132 kJ / kg ⋅ K at temperature 560 ° C and 160 bar . Refer to Table A-3, “Properties of Saturated Water (Liquid–Vapor): Pressure Table”, to obtain specific enthalpy of liquid as 173.9 kJ / kg , specific enthalpy of vaporization 2403.2 kJ / kg , specific entropy of liquid 0.593 kJ / kg ⋅ K , specific entropy of vaporization as 7.657 kJ / kg ⋅ K and specific volume 1.008 × 10 − 3 m 3 / kg at pressure 0.08 bar . Refer to Table A-3, “Properties of Saturated Water (Liquid–Vapor): Pressure Table”, to obtain specific enthalpy of liquid as 762.6 kJ / kg , specific enthalpy of vaporization 2013.6 kJ / kg , and the specific entropy of liquid 2.138 kJ / kg ⋅ K and specific entropy of vaporization as 4.445 kJ / kg ⋅ K and specific volume of liquid 1.127 × 10 − 3 m 3 / kg at pressure 10 bar and the specific entropy is superheated region at 10 bar as 6.7451 kJ / kg ⋅ K . Substitute 6.5132 kJ / kg ⋅ K for s 2 s , 2.138 kJ / kg ⋅ K for s f and 4.445 kJ / kg ⋅ K for s f g in Equation (I). 6.5132 kJ / kg ⋅ K = ( 2.138 kJ / kg ⋅ K ) + x 2 s × ( 4.445 kJ / kg ⋅ K ) x 2 s = ( 6.5132 kJ / kg ⋅ K ) − ( 2.138 kJ / kg ⋅ K ) ( 4.445 kJ / kg ⋅ K ) x 2 s = 0.984 Substitute 762.6 kJ / kg for h f , 0.984 for x 2 s and 2013.6 kJ / kg for h f g in Equation (II). h 2 s = 762.6 kJ / kg + 0.984 × 2013.6 kJ / kg = 762.6 kJ / kg + 1981.3824 kJ / kg = 2744 kJ / kg Substitute 0.85 for η T , 3465.4 kJ / kg for h 1 and 2744 kJ / kg for h 2 s in Equation (III). h 2 = 3465.4 kJ / kg − 0.85 ( 3465.4 kJ / kg − 2744 kJ / kg ) = 3465.4 kJ / kg − 613.19 kJ / kg = 2852.21 kJ / kg Substitute 6.7451 kJ / kg ⋅ K for s 3 s , 0.593 kJ / kg ⋅ K for s f and 7 (b) To determine The rate of heat transfer to the steam passing through the boiler. (c) To determine The thermal efficiency. (d) To determine The mass flow rate of condenser cooling water.

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118832301

Author: SHAPIRO

Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT

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Chapter 8.6, Problem 48P

(a)

To determine

The net power developed.

(b)

To determine

The rate of heat transfer to the steam passing through the boiler.

(c)

To determine

The thermal efficiency.

(d)

To determine

The mass flow rate of condenser cooling water.

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Chapter 8.6, Problem 47P

Chapter 8.6, Problem 49P

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Chapter 8 Solutions

Fundamentals of Engineering Thermodynamics

Ch. 8.6 - Prob. 1E Ch. 8.6 - Prob. 2E Ch. 8.6 - Prob. 3E Ch. 8.6 - Prob. 4E Ch. 8.6 - Prob. 5E Ch. 8.6 - Prob. 6E Ch. 8.6 - Prob. 7E Ch. 8.6 - 8. What is the relationship between global climate...Ch. 8.6 - Prob. 9E Ch. 8.6 - Prob. 10E

Ch. 8.6 - Prob. 11E Ch. 8.6 - Prob. 12E Ch. 8.6 - Prob. 13E Ch. 8.6 - Prob. 1CU Ch. 8.6 - Prob. 2CU Ch. 8.6 - 3. The component of the Rankine cycle in which the...Ch. 8.6 - 4. A cycle that couples two vapor cycles so the...Ch. 8.6 - 5. The ratio of the pump work input to the work...Ch. 8.6 - 6. A shell-and-tube-type recuperator in which the...Ch. 8.6 - Prob. 7CU Ch. 8.6 - Prob. 8CU Ch. 8.6 - Prob. 9CU Ch. 8.6 - Prob. 10CU Ch. 8.6 - 11. An example of an external irreversibility...Ch. 8.6 - Prob. 12CU Ch. 8.6 - Prob. 13CU Ch. 8.6 - Prob. 14CU Ch. 8.6 - 15. A direct-contact–type heat exchanger found in...Ch. 8.6 - 16. The component of a regenerative vapor power...Ch. 8.6 - Prob. 17CU Ch. 8.6 - 18. A Rankine cycle that employs an organic...Ch. 8.6 - Prob. 19CU Ch. 8.6 - Prob. 20CU Ch. 8.6 - Prob. 21CU Ch. 8.6 - Prob. 22CU Ch. 8.6 - Prob. 23CU Ch. 8.6 - 24. The purpose of deaeration is ______________. Ch. 8.6 - Prob. 25CU Ch. 8.6 - Prob. 26CU Ch. 8.6 - Prob. 27CU Ch. 8.6 - Prob. 28CU Ch. 8.6 - 29. The total cost associated with a power plant...Ch. 8.6 - Prob. 30CU Ch. 8.6 - Prob. 31CU Ch. 8.6 - Prob. 32CU Ch. 8.6 - Prob. 33CU Ch. 8.6 - Prob. 34CU Ch. 8.6 - Prob. 35CU Ch. 8.6 - Prob. 36CU Ch. 8.6 - Prob. 37CU Ch. 8.6 - Prob. 38CU Ch. 8.6 - Prob. 39CU Ch. 8.6 - 40. For a vapor power cycle with and , the...Ch. 8.6 - Prob. 41CU Ch. 8.6 - Prob. 42CU Ch. 8.6 - Prob. 43CU Ch. 8.6 - Prob. 44CU Ch. 8.6 - Prob. 45CU Ch. 8.6 - Prob. 46CU Ch. 8.6 - Prob. 47CU Ch. 8.6 - Prob. 48CU Ch. 8.6 - Prob. 49CU Ch. 8.6 - 50. In a binary cycle, energy discharged by heat...Ch. 8.6 - Prob. 1P Ch. 8.6 - Prob. 2P Ch. 8.6 - Prob. 3P Ch. 8.6 - Prob. 6P Ch. 8.6 - 8.7 Water is the working fluid in an ideal Rankine...Ch. 8.6 - Prob. 8P Ch. 8.6 - 8.10 Water is the working fluid in an ideal...Ch. 8.6 - Prob. 12P Ch. 8.6 - Prob. 13P Ch. 8.6 - 8.14 On the south coast of the island of Hawaii,...Ch. 8.6 - Prob. 15P Ch. 8.6 - 8.17. Water is the working fluid in a Rankine...Ch. 8.6 - 8.19 Water is the working fluid in a Rankine...Ch. 8.6 - Prob. 20P Ch. 8.6 - Prob. 21P Ch. 8.6 - 8.22 Superheated steam at 8 MPa and 480°C leaves...Ch. 8.6 - Prob. 23P Ch. 8.6 - Prob. 25P Ch. 8.6 - Prob. 26P Ch. 8.6 - 8.27 Steam is the working fluid in the ideal...Ch. 8.6 - Prob. 28P Ch. 8.6 - Prob. 29P Ch. 8.6 - Prob. 30P Ch. 8.6 - Prob. 31P Ch. 8.6 - 8.32 An ideal Rankine cycle with reheat uses water...Ch. 8.6 - Prob. 33P Ch. 8.6 - 8.34 Steam at 4800 lbf/in.2, 1000℉ enters the...Ch. 8.6 - Prob. 35P Ch. 8.6 - Prob. 37P Ch. 8.6 - 8.38 For the cycle of Problem 8.37, reconsider the...Ch. 8.6 - Prob. 39P Ch. 8.6 - Prob. 40P Ch. 8.6 - Prob. 41P Ch. 8.6 - Prob. 42P Ch. 8.6 - Prob. 43P Ch. 8.6 - Prob. 44P Ch. 8.6 - Prob. 45P Ch. 8.6 - Prob. 46P Ch. 8.6 - Prob. 47P Ch. 8.6 - 8.48 For the cycle of Problem 8.47, investigate...Ch. 8.6 - Prob. 49P Ch. 8.6 - Prob. 50P Ch. 8.6 - Prob. 51P Ch. 8.6 - 8.52 As indicated in Fig. P8.52, a power plant...Ch. 8.6 - Prob. 53P Ch. 8.6 - Prob. 54P Ch. 8.6 - Prob. 55P Ch. 8.6 - Prob. 56P Ch. 8.6 - Prob. 57P Ch. 8.6 - Prob. 58P Ch. 8.6 - Prob. 59P Ch. 8.6 - Prob. 60P Ch. 8.6 - Prob. 61P Ch. 8.6 - Prob. 63P Ch. 8.6 - Prob. 64P Ch. 8.6 - Prob. 65P Ch. 8.6 - Prob. 66P Ch. 8.6 - 8.67 Water is the working fluid in a Rankine cycle...Ch. 8.6 - Prob. 68P Ch. 8.6 - Prob. 69P Ch. 8.6 - Prob. 70P Ch. 8.6 - 8.72 Water is the working fluid in a...Ch. 8.6 - Prob. 73P Ch. 8.6 - Prob. 74P Ch. 8.6 - Prob. 75P Ch. 8.6 - 8.76 A binary vapor power cycle consists of two...Ch. 8.6 - A binary vapor cycle consists of two Rankine...Ch. 8.6 - Prob. 78P Ch. 8.6 - Prob. 79P Ch. 8.6 - Prob. 80P Ch. 8.6 - 8.81 Figure P8.81 shows a combined heat and power...Ch. 8.6 - 8.82 Figure P8.82 shows a cogeneration cycle that...Ch. 8.6 - Prob. 83P Ch. 8.6 - 8.84 The steam generator of a vapor power plant...Ch. 8.6 - 8.85 Determine the exergy input, in kJ per kg of...Ch. 8.6 - 8.86 In the steam generator of the cycle of...Ch. 8.6 - Prob. 87P Ch. 8.6 - 8.88 Determine the rate of exergy input, in Btu/h,...Ch. 8.6 - Prob. 89P Ch. 8.6 - Prob. 90P Ch. 8.6 - Prob. 91P Ch. 8.6 - 8.92 Figure P8.92 provides steady-state operating...Ch. 8.6 - 8.93 Steam enters the turbine of a simple vapor...

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