Chapter 8.6, Problem 3TFS

To determine

To calculate: The dimensions of rectangle if the perimeter of rectangle is 2347ft. whose length is 28 ft greater than the width of the rectangle and match the answer with the options below.

$\begin{array}{l}A.x+\left(x-3\right)+\frac{4}{5}x=384\\ B.x+\left(x+51\right)+\left(2x-3\right)=180\\ C.x+\left(x+96\right)=180\\ D.2\cdot 96+2x=3976\end{array}$

And,

$\begin{array}{l}E.x+\left(x+1\right)+\left(x+2\right)=384\\ F.3976=x\cdot 11,360\\ G.2x+2\left(x+28\right)=2347\\ H.3976=x+5\%x\end{array}$

And,

$\begin{array}{l}I.x+\left(x+28\right)=2347\\ J.x=35\%\cdot 11,360\\ K.x+96=3976\\ L.x+\left(x+3\right)+\frac{4}{5}x=384\end{array}$

And,

$\begin{array}{l}M.x\left(x+2\right)+\left(x+4\right)=384\\ N.35\%\cdot x=3976\\ O.2x+\left(x+28\right)=2347\end{array}$