Explanation Given Information: The provided equation is, 5 ( 3 y − 1 ) = − 35 . Formula used: Addition property: If a = b , then a + c = b + c , where a , b , and c are any real numbers. Divisionproperty: If a = b , then a c = b c , where a , b , and c are any real numbers and c ≠ 0 . Distributive property: For any real numbers a , b , c ; a ( b + c ) = a b + a c . Calculation: Consider the provided equation, 5 ( 3 y − 1 ) = − 35 Apply distributive property to remove the parentheses on left side of the equation. 5 ⋅ 3 y − 5 ⋅ 1 = − 35 15 y − 5 = − 35 By addition property stated above, add both sides of the equation by 5 . 15 y − 5 + 5 = − 35 + 5 15 y = − 30 By division property stated above, divide both sides of the equation by 15

9th Edition

ISBN: 9780321997173

Author: Marvin L. Bittinger, Judith A. Beecher

Publisher: PEARSON

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Chapter 8.4, Problem 35MCR

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To calculate: The solution of the equation 5(3y−1)=−35.

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Chapter 8.4, Problem 34MCR

Chapter 8.4, Problem 36MCR

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Chapter 8 Solutions

Developmental Mathematics (9th Edition)

Ch. 8.1 - Objective 7.1a: Evaluate algebraic expressions by...Ch. 8.1 - Prob. 2SR Ch. 8.1 - Prob. 1DE Ch. 8.1 - Prob. 2DE Ch. 8.1 - Prob. 3DE Ch. 8.1 - Prob. 4DE Ch. 8.1 - Prob. 5DE Ch. 8.1 - Prob. 6DE Ch. 8.1 - Prob. 7DE Ch. 8.1 - Prob. 8DE

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The solution of the equation 5 ( 3 y − 1 ) = − 35 .

Solution Summary: The author calculates the solution of the equation 5(3y-1)=-35.

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To calculate: The solution of the equation 5(3y−1)=−35.

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Chapter 8 Solutions