Explanation Given: n = 30 , p = 0.6 and q = 0.4 . Approach: The expression to obtain the probabilities are as follows, P ( X > a ) = P ( Z > a − μ σ ) … ( 1 ) and P ( X < a ) = P ( Z < a − μ σ ) … ( 2 ) Here, P ( X ) is the Probability of an event, Z is the range, μ is the mean, σ is a standard deviation. The expressions to obtaining the mean and standard variation. μ = n p … ( 3 ) σ = n p q … ( 4 ) Calculation: Consider the equation of mean. Substitute 30 for n , 0.6 for p in equation ( 3 ) μ = 30 × 0 To determine (b). The probability of his hitting the target fewer than 10 times. To determine (c). The probability of his hitting the target between 15 and 20 times, inclusive

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ISBN: 8220103649001

Author: Tan

Publisher: CENGAGE L

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Chapter 8.6, Problem 15E

To determine

(a).

The probability of his hitting the target

To determine

(b).

The probability of his hitting the target fewer than 10 times.

To determine

(c).

The probability of his hitting the target between 15 and 20 times, inclusive

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Chapter 8.6, Problem 14E

Chapter 8.6, Problem 16E

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(a). The probability of his hitting the target

Solution Summary: The author explains how to determine the probability of hitting the target at least 20 times.

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(a). The probability of his hitting the target

(b). The probability of his hitting the target fewer than 10 times.

(c). The probability of his hitting the target between 15 and 20 times, inclusive

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Chapter 8 Solutions

(a).

The probability of his hitting the target

(b).

The probability of his hitting the target fewer than 10 times.

(c).

The probability of his hitting the target between 15 and 20 times, inclusive