Explanation Given: Number of players selected at random is 10 . Probability of defective players produced is 0.02 . Approach: The expanded expression of C ( n , x ) is given as; C ( n , x ) = n ! x ! ( n − x ) ! If p is the probability of success of an event and q is the probability of failure of an event. Then, the relationship between p and q is given as: q = 1 − p The probability of x successes in n independent trials is given by, P ( X = x ) = C ( n , x ) p x q n − x Such that, x = 0 , 1 , 2 , 3 ......... , n Here, X is the binomial random variable and the probability distribution of X is called a binomial distribution. Calculation: Let X denote the number defective players. Number of players selected at random is, n = 10 Probability of defective player is, p = 0.02 Calculate the value of q . Substitute 0.02 for p in the expression for q . q = 1 − 0.02 = 0 To determine (b) The probability that the sample contains at most two defective players.

12th Edition

ISBN: 8220103649001

Author: Tan

Publisher: CENGAGE L

See similar textbooks

Concept explainers

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear re…

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.

Videos

Question

Chapter 8.4, Problem 37E

To determine

(a)

The probability that the sample contains no defective players.

To determine

(b)

The probability that the sample contains at most two defective players.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 8.4, Problem 36E

Chapter 8.4, Problem 38E

Students have asked these similar questions

A crate is supported by three cables as shown. Determine the weight of the crate knowing that the tension in cable AB is 750 lb

+ 32 in. B 36 in. 40 in. A 60 in. X 27 in.

Equilibrium Equations: Two-dimensional 2.28 Ra= Rc= 2.29 (change force to 600N) AC= AB= 2.33 CD= AC= DE= BC= Free Body Diagrams 2.34 Ax= Ay=_ Bx= By= 2.36 Ax= Ay= Bx= By= 2.37 (change middle force to 4000 lbs) Ay=_ Dx= Dy=_ 2.38 (change horizontal force to 2 kN) Ax= Ay= Bx= By=_ 2.40 Ay= By= Dx= 32% Bx= Cy= Dy=

Chapter 8 Solutions

EBK FINITE MATHEMATICS FOR THE MANAGERI

Ch. 8.1 - What is a random variable? Give an example.Ch. 8.1 - Prob. 2CQ Ch. 8.1 - Prob. 3CQ Ch. 8.1 - Three balls are selected at random without...Ch. 8.1 - 2.A coin is tossed four times. Let the random...Ch. 8.1 - A die is rolled repeatedly until a 6 falls...Ch. 8.1 - Cards are selected one at a time without...Ch. 8.1 - Prob. 5E Ch. 8.1 - Prob. 6E Ch. 8.1 - Prob. 7E

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.

(a) The probability that the sample contains no defective players.

Solution Summary: The author explains that the probability of the sample contains no defective players is 0.817.